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Vadim26 [7]
3 years ago
8

Math I need help I'm trying to pass 6th

Formula1" title="-6 + (-1) + (-4) =" alt="-6 + (-1) + (-4) =" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

-11

Step-by-step explanation:

-6+(-1)+(-4)=-11

I hope this helps, I also think this is the answer!.

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Find the area of a circle with a circumference of 31.5 units
Westkost [7]

Answer:

79 units²

Step-by-step explanation:

The area of a circle is found by using the formula A = π x r². Since we are not given the radius we can use the formula r = C / (2π). Substituting in the given values, we get r = 31.5/(2π). 2 times pi is 6.283185307. 31.5 divided by this will get you 5.013380707. Now, put that value in for r in the area equation. A = π x 5.013380707². Pi times 5.013380707² equals 78.96074613. This can be rounded to 79. (Or 80 if you need to the nearest whole number.)

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3 years ago
Factor 2x2+25x+50. Rewrite the trinomial with the x-term expanded, using the two factors.
zlopas [31]

9514 1404 393

Answer:

  • rewrite: 2x^2 +5x +20x +50
  • factored: (x +10)(2x +5)

Step-by-step explanation:

I find this approach the most straightforward of the various ways that trinomial factoring is explained or diagramed.

You want two factors of "ac" that have a total of "b". Here, that means you want factors of 2·50 = 100 that have a total of 25. It is helpful to know your times tables.

  100 = 1·100 = 2·50 = 4·25 = 5·20 = 10·10

The sums of these factor pairs are 101, 52, 29, 25, and 20. We want the pair with a sum of 25, so that's 5 and 20.

The trinomial can be rewritten using these factors as ...

  2x^2 +5x +20x +50

Then it can be factored by grouping consecutive pairs:

  (2x^2 +5x) +(20x +50) = x(2x +5) +10(2x +5) = (x +10)(2x +5)

_____

<em>Additional comment</em>

It doesn't matter which of the factors of the pair you write first. If our rewrite were ...

  2x^2 +20x +5x +50

Then the grouping and factoring would be (2x^2 +20x) +(5x +50)

  = 2x(x +10) +5(x +10) = (2x +5)(x +10) . . . . . same factoring

6 0
2 years ago
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