Answer:
Step-by-step explanation:
To find the equation of a sphere with center (2,-3,6) that touch
(a) the xy-plane,
The equation of xy plane is z=0
Hence the radius would be distance from z=0 perpendicular to xy plane = z coordinate =6
Equation is
(b) the yz-plane,
The equation of yz plane is x=0
Hence the radius would be distance from x=0 perpendicular to yz plane = x coordinate =2
Equation is
(c) the xz-plane.
The equation of zx plane is y=0
Hence the radius would be distance from y=0 perpendicular to zx plane = |y coordinate| =3
Equation is
Note that the difference keeps increasing by a value of 10. Hence the next term of the sequence is 110
<h3>Geometric sequence </h3>
Geometric sequence are sequence that increase in an exponential manner.
Given the recursive sequence 0, 2, 14, 36, 68
From the sequence
0 + 2 = 2
2 + 12 = 14
14 + 22 = 36
36 + 32 = 68
68 + 42 = 110
Note that the difference keeps increasing by a value of 10. Hence the next term of the sequence is 110
Learn more on sequence here: brainly.com/question/6561461
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Answer:
Step-by-step explanation:
<span>I think it's 25 but I can be wrong..</span>
Answer:
Your answer is C. Hope this helped. :)
Step-by-step explanation:
a^2 + b^2 = c^2
32^2 + 18^2 = c^2
1024 + 324 = c^2
√(1348) = 36.7
= 37