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Sonbull [250]
3 years ago
12

Weinstein, McDermott, and Roediger report that students who were givne questions to be answered while studying new material had

better scores when tested on the material compared to students who were simply given an opportunity to reread the material. In a similiar study, an instructor in a large psychology class gave one group of students questions to be answered while studying for the final exam. The overall average for the exam was mean = 73.4, but the n = 16 students who answered questions had a mean of M =78.3 with a standard deviation of s=8.4. For this study, did answering questions while studying produce significantly higher exam scores? Use a one tailed test with alpha = .01.
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By considering the given information , we have

Null hypothesis : H_0: \mu=73.4

Alternative hypothesis :  H_a: \mu>73.4

Since alternative hypothesis is right-tailed , so the test is a right-tailed test.

Given : Sample size : n=16 , which is a small sample , so we use t-test.

Sample mean: \overline{x}=78.3  ;

Standard deviation: s=8.4

Test statistic for population mean:

t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e. t=\dfrac{78.3-73.4}{\dfrac{8.4}{\sqrt{16}}}\approx2.333

Using the standard normal distribution table of t , we have

Critical value for \alpha=0.01 : t_{(n-1,\alpha)}=t_{(15,0.01)}=2.602

Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.

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The scores of five students on a quiz are 11, 21, 16, 7, and 10. Find the mean and median of the scores.
photoshop1234 [79]
Hello!

The mean is the average. To calculate it you add up all the numbers, and divide by how many numbers there were. So for example, if you had 1 and 3, you would add them and divide by two since there were two numbers. We will calculate the mean of this data set below.

(11+21+16+7+10)=65
65/5=13

The mean of the data set is 13.
---------------------------------------------------------------------------------------
Now we need to find the median. To do so we have to first order all of the numbers from least to greatest.

7,10,11,16,21

Now we have to find the number in the middle of the data set.

11 is our median. (Note that when calculating the median with an even number of data points, you will find the mean of the two center numbers)

I hope this helps!


4 0
3 years ago
Gary has four times as many points as Frank. Evan has five times as many as Frank. Dave is two times as many as Frank. altogethe
tensa zangetsu [6.8K]

Answer:

the answer to this would be 114 i think sorry is im wrong

Step-by-step explanation:

7 0
2 years ago
I have no clue i came up with 0.6 but that's wrong according to them :[
NISA [10]

Answer:

the answer is 0.6 there is prob a glitch in th system or we r doing something wrong

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Number 2 and please explain
exis [7]
Part of it is cut out
4 0
3 years ago
C) How many times would you expect to roll a 5 when<br> a fair dice is thrown 3000 times?
Ray Of Light [21]

Answer:

500

Step-by-step explanation:

The probability is 1/6.

So, find 1/6 of 3,000.

1/6 * 3,000 = 3,000/6 = 500

3 0
2 years ago
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