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Sonbull [250]
3 years ago
12

Weinstein, McDermott, and Roediger report that students who were givne questions to be answered while studying new material had

better scores when tested on the material compared to students who were simply given an opportunity to reread the material. In a similiar study, an instructor in a large psychology class gave one group of students questions to be answered while studying for the final exam. The overall average for the exam was mean = 73.4, but the n = 16 students who answered questions had a mean of M =78.3 with a standard deviation of s=8.4. For this study, did answering questions while studying produce significantly higher exam scores? Use a one tailed test with alpha = .01.
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By considering the given information , we have

Null hypothesis : H_0: \mu=73.4

Alternative hypothesis :  H_a: \mu>73.4

Since alternative hypothesis is right-tailed , so the test is a right-tailed test.

Given : Sample size : n=16 , which is a small sample , so we use t-test.

Sample mean: \overline{x}=78.3  ;

Standard deviation: s=8.4

Test statistic for population mean:

t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e. t=\dfrac{78.3-73.4}{\dfrac{8.4}{\sqrt{16}}}\approx2.333

Using the standard normal distribution table of t , we have

Critical value for \alpha=0.01 : t_{(n-1,\alpha)}=t_{(15,0.01)}=2.602

Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.

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S_A_V [24]

Answer: D. 453 miles .

Step-by-step explanation:

Given: The function d(t)=458-60t models the distance, in miles, that Jessica is from her house <em>t </em>hours after she began returning home.

At t = 5 minutes = \dfrac{5}{60} hour     [1 hour = 60 minutes],

Distance covered by Jessica in 5 minutes = d(\dfrac{5}{60})=458-60(\dfrac{5}{60})

=458-5=453\ miles

Jessica is 453 miles from her home after 5 minutes she began returning home.

Hence, the correct option is D. 453 miles .

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jek_recluse [69]

Answer:

(p - 7)(2p - 5)

Step-by-step explanation:

2 {p}^{2}  - 19p + 35 \\  \\  = 2 {p}^{2}  - 14p - 5p + 35 \\  \\  = 2p(p - 7) - 5(p - 7) \\  \\  = (p - 7)(2p - 5)

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This is in the form of a slope formula where y=mx+b. B pretty much gives you the vertical shift. Meaning that y=2/x-3 would be correct.
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Write the following ratios in its simplest form 56:112:28
damaskus [11]

Answer:

<u>2 : 4 : 1</u>

Step-by-step explanation:

First take common factors by factorization.

56 = 14 x 4 = 28 x 2

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Remove the 28 common factor.

Therefore,

56 : 112 : 28

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