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Sonbull [250]
2 years ago
12

Weinstein, McDermott, and Roediger report that students who were givne questions to be answered while studying new material had

better scores when tested on the material compared to students who were simply given an opportunity to reread the material. In a similiar study, an instructor in a large psychology class gave one group of students questions to be answered while studying for the final exam. The overall average for the exam was mean = 73.4, but the n = 16 students who answered questions had a mean of M =78.3 with a standard deviation of s=8.4. For this study, did answering questions while studying produce significantly higher exam scores? Use a one tailed test with alpha = .01.
Mathematics
1 answer:
emmainna [20.7K]2 years ago
3 0
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By considering the given information , we have

Null hypothesis : H_0: \mu=73.4

Alternative hypothesis :  H_a: \mu>73.4

Since alternative hypothesis is right-tailed , so the test is a right-tailed test.

Given : Sample size : n=16 , which is a small sample , so we use t-test.

Sample mean: \overline{x}=78.3  ;

Standard deviation: s=8.4

Test statistic for population mean:

t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}

i.e. t=\dfrac{78.3-73.4}{\dfrac{8.4}{\sqrt{16}}}\approx2.333

Using the standard normal distribution table of t , we have

Critical value for \alpha=0.01 : t_{(n-1,\alpha)}=t_{(15,0.01)}=2.602

Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.

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Please Help- <br> K + ⅓ = 5 ⅛ | K = ?<br> Show Your Reasoning.
blondinia [14]

Answer:

4\frac{19}{24}

Step-by-step explanation:

I hope I did this right:

So first thing to do is set up the equation.

K + \frac{1}{3} = 5\frac{1}{8}

Next thing to to is subtract 1/3 from both sides to get:

K = 5\frac{1}{8} - \frac{1}{3}

Next up, you will multiply each of the fractions by the opposing value

(multiply 1/8 by 3 and 1/3 by 8)

K = 5\frac{3}{24}-\frac{8}{24}

Alright almost done, by multiplying 24 by 5 you get 120, that will go in the numerator to make the math a lot easier.

K = \frac{123}{24}-\frac{8}{24}

Finally, you subtract 123 over 24 by 8 over 24.

K = \frac{123}{24} - \frac{8}{24} = \frac{115}{24}

Then just simplfy the 115/24 to get

4\frac{19}{24}

8 0
2 years ago
What is the product of (3a + 2)(4a? - 2a + 9)?
yan [13]

Answer:

The answer is 12a^3+2a²+23a+18 ....

Step-by-step explanation:

The given terms are:

(3a + 2)(4a² - 2a + 9)

Now multiply each value of second bracket with the first bracket:

=4a²(3a+2) -2a(3a+2)+9(3a+2)

=12a^3+8a²-6a²-4a+27a+18

Solve the like terms:

=12a^3+2a²+23a+18

Therefore the answer is 12a^3+2a²+23a+18 ....

4 0
2 years ago
5c + 3 ≥ 6x -8<br><br> Solve the following inequality for cc. Write your answer in simplest form.
irina [24]

Answer:

c≥2(x-2) ÷ 5

Step-by-step explanation:

5c+3≥6x-8

5c ≥6x-8-3

5c≥6x-12

c≥(6x-12) ÷ 5

c≥ 2(x-2) ÷5

3 0
2 years ago
9. Evaluate (-7) -10 ÷ (-28)-10<br> pls solve fast
Juli2301 [7.4K]

Answer:

17/38 or ≈ 0.45

Step-by-step explanation:

(-7) -10 / (-28)-10

= -17 / -38

= 17/38

You can keep the answer in fraction as 17/38 or ≈ 0.45

Hope this help you :3

7 0
2 years ago
Help!! Plz complete these two :)
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