947 i thinkkk sugejegdjehrhdhhed
Answer:
Step-by-step explanation:
Mark any two point on the line
(-1 , 0) & (-3 , -1)
Slope = 
![= \frac{-1-0}{-3-[-1]}\\\\= \frac{-1}{-3+1}\\\\= \frac{-1}{-2}\\\\= \frac{1}{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-1-0%7D%7B-3-%5B-1%5D%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-1%7D%7B-3%2B1%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-1%7D%7B-2%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7B2%7D)
m = 1/2 ; (-1 , 0)
Equation: 
![y - 0 = \frac{1}{2}(x - [-1])\\\\y = \frac{1}{2}(x + 1)\\\\y = \frac{1}{2}x + \frac{1}{2}](https://tex.z-dn.net/?f=y%20-%200%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28x%20-%20%5B-1%5D%29%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28x%20%2B%201%29%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20%2B%20%5Cfrac%7B1%7D%7B2%7D)
Answer:
35
Step-by-step explanation:
Given
n (A) = 15
n (B) = 20
Students who do not like any subject = 5
Hence, number of students who would like either both or either of the two subjects = 60-5 = 55
n (A or B) = n (A) + n (B) - n (A and B)
Number of students linking both the subjects
55 - 15-20
= 55-35 = 20
Number of students linking only one subject = 60-20-5 = 35
Point slope form is y - y1 = m(x - x1)
so if the slope is m= 2 and (x1,y1) = (1,3) is a point on the line the equation is:-
y - 3 = 2(x - 1)
Answer:
the answer is c
Step-by-step explanation:
because the probability is 0.72 planes are more likely to take off on time unless there is a technical problem
