Please help me!! I need help

Mathematics

2 answers:

Shkiper50 [21]2 years ago

8 0

Answer:

Since they're asking you to find the missing sides "y" and "x" here's what you need to do....

Step-by-step explanation:

1) This is the 45-45-90 Triangle.

2) y = 20 becasue this is an isocelese triangle - meaning a triangle that has 2 sides of equal lengths!

3) in order to find x (which is the hyptoneus) you have to do

$\sqrt{2}$ * leg (use on of the legs)

= $20\sqrt{2}$

also I think 45 degrees is there just to throw you off. And I'm pretty positive this is the correct answer, and i'm 100% sure that y = 20 is correct!

Setler [38]2 years ago

7 0

Answer:

c=l/--a^2+b^2=l/--45^2+20^2≈49.24429

Step-by-step explanation:

l/-- mean square root

^ means squared/ exponent

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Lesechka [4]

If these 2 triangles are similar to each other, the corresponding sides have to exist in proportion to one another. The angles would be exactly the same (side length doesn't matter at all!). Going from the bigger triangle to the smaller, KL corresponds to RS; LJ corresponds to SQ; JK corresponds to QR. The ratio of KL:RS is 5:1; the ratio of LJ:SQ is 5:1; the ratiio of JK:QR is 5:1. That means that the sides are all proportionate and the triangles are similar by the SSS postulate. Now that we know that the triangles are similar, we can say that all the corresponding angles are the same by CPCTC but we had to determinte side similiarity first. Your answer is the second choice, SSS

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Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b

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Answer:

Step-by-step explanation:

From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .

So; as each place is fitted with either 0 or 1

$\mathbf{|R|= 2^{10}}$

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

$\mathbf{P(E) = \dfrac{|E|}{|R|}}$