1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara [203]
2 years ago
15

Please help me!! I need help

Mathematics
2 answers:
Shkiper50 [21]2 years ago
8 0

Answer:

Since they're asking you to find the missing sides "y" and "x" here's what you need to do....

Step-by-step explanation:

1) This is the 45-45-90 Triangle.

2) y = 20 becasue this is an isocelese triangle - meaning a triangle that has 2 sides of equal lengths!

3) in order to find x (which is the hyptoneus) you have to do

       \sqrt{2} * leg (use on of the legs)

    =  20\sqrt{2}

also I think 45 degrees is there just to throw you off. And I'm pretty positive this is the correct answer, and i'm 100% sure that y = 20 is correct!

Setler [38]2 years ago
7 0

Answer:

c=l/--a^2+b^2=l/--45^2+20^2≈49.24429

Step-by-step explanation:

l/-- mean square root

^ means squared/ exponent

You might be interested in
Someone please help me
Lesechka [4]

If these 2 triangles are similar to each other, the corresponding sides have to exist in proportion to one another. The angles would be exactly the same (side length doesn't matter at all!). Going from the bigger triangle to the smaller, KL corresponds to RS; LJ corresponds to SQ; JK corresponds to QR. The ratio of KL:RS is 5:1; the ratio of LJ:SQ is 5:1; the ratiio of JK:QR is 5:1. That means that the sides are all proportionate and the triangles are similar by the SSS postulate. Now that we know that the triangles are similar, we can say that all the corresponding angles are the same by CPCTC but we had to determinte side similiarity first. Your answer is the second choice, SSS

8 0
3 years ago
Can someone please help me .
dusya [7]

Answer:

for 10. a

for 11. f.

Step-by-step explanation:

5 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 b
jeka94

Answer:

Step-by-step explanation:

From the given information; Let's assume that  R should represent the set of all possible outcomes generated from  a bit string of length 10 .

So; as each place is fitted with either 0 or 1

\mathbf{|R|= 2^{10}}

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0

Now;

if  a 0 bit and a 1 bit are equally likely

The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

\mathbf{P(E) = \dfrac{|E|}{|R|}}

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:

\mathbf{{|E|}=1 }   ; \mathbf{|R|= 2^{10}}

\mathbf{P(E) = \dfrac{1}{2^{10}}}

4 0
3 years ago
Drag the ordered pairs to match the points shown on the coordinate grid.
Kobotan [32]

Answer:

A) (3, 6)

B) (2, 3)

C) (4, 2)

D) (6, 0)

4 0
2 years ago
Read 2 more answers
2. If a person is walking at a pace of 2/3 mile every 2/5 hour, how long would it take
viva [34]
It would take them a half and hour
3 0
3 years ago
Other questions:
  • She paid 26.35 for something that would be 31 what percent discount did she get
    8·1 answer
  • The table below lists recommended amounts of food to order for 60 party guests. How much of each food item should Nathan and Ama
    12·1 answer
  • What is the answer to 8(8k-8)​
    13·2 answers
  • What is 9 more then the sum of a number and three is 35 into a equation
    9·1 answer
  • 8251 is 127% of what number
    5·1 answer
  • Answer this question for please!Describe the steps.Thanks!
    11·1 answer
  • Someone please answer this! THANKSSSS
    15·2 answers
  • Help me asap please help me help thank you
    12·1 answer
  • 18<br> 19<br> O 18-1/4<br> O<br> 1/4"<br> 1-1/4
    9·1 answer
  • HELPPPP really quick
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!