For this case we have the following function:

By definition, we have that the domain of a function is given by all the values for which the function is defined. The given function is not defined when the denominator is zero.
So:

Thus, the function is not defined at 
The domain is given by all real numbers except 2.
Answer:
The domain is given by all real numbers except 2.
Answer: D) 13y^25 and 2y^25
Like terms involve the same variables, and each of those variables must have the same exponents.
Another example of a pair of like terms would be 5x^3y^2 and 7x^3y^2. Both involve the variable portion "x^3y^2" which we can replace with another variable, say the variable z. That means 5x^3y^2 becomes 5z and 7x^3y^2 becomes 7z. After getting to 5z and 7z, it becomes more clear we have like terms.
I think it has 2 pairs of parallel sides
Answer:
[-4,9)
Step-by-step explanation:
im like 99% sure this is right bc i just did a problem like this (:
Answer:
y= 3/2x+40
Step-by-step explanation:
y= rise/run+ y-intercept