Answer:
y = -x + 5
y = x/2 + 3/2
Step-by-step explanation:
First we calculate the slope as difference between coordinates
a) P₁ ( -1 , 6 ) P₂ ( 3 , 2 )
m = Δy/Δx ⇒ m = ( y₂ - y₁ ) / ( x₂ - x₁ ) ⇒ m = (2 -6 ) / (3 -(-1))
m = -4 /4
m = -1
Now we have:
y - y₁ = m ( x - x₁ ) ⇒ y - 6 = (-1) ( x - (-1))
y - 6 = -1 * ( x + 1 ) ⇒ y - 6 = - x - 1
y = -x + 5
In the second case
Q₁ ( -3 , 0 ) Q₂ ( 5 , 4 )
Again we calculate the slope
m = Δy / Δx ⇒ m = ( 4 - 0 ) / ( 5 - (-3)) ⇒ m = 4 / 8 ⇒ m = 1/2
m = 1/2 or x = 0,5
And
y - y₁ = 1/2 ( x - x₁ ) ⇒ y - y₁ = 1/2 ( x - (-3)) ⇒ y - 0 = 1/2 * x + 3/2
y = x/2 + 3/2
In order to solve this we must first,
Subtract both sides of the equation by 10,
y-10=1/2x
Now we have to multiply both sides by 2 so that only x is left.
2y-20=x
Therefore, x=2y-20
Answer: 3x-y=10 , 6x-2y=5. 3x−y=10 3 x - y = 10 , 6x−2y=5 6 x - 2 y = 5. Solve for y y in the first equation. Tap for more steps... Subtract 3x 3 x from
Graph y=6x-10 |
Answer:
F. a1 = –5, an = 5an-1
Step-by-step explanation:
a1 = -5 <---- Answer
r = -25/-5 = 5
an = r(an - 1)
an = 5(an - 1) <---- Answer
Hope this helps!
If the ends span from the 0 to the 15 meter mark, then the length of the pipe is 15 meters. However, you should report it using the right amount of significant figures. It is mentioned in the problem that millimeter marks are calibrated between meters. Since millimeter is 1/1000 of a meter, you should add three decimal places to the 15 meters. Hence, you should report it as 15.000 meters.
