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Ray Of Light [21]
3 years ago
13

Please help please.......​

Mathematics
1 answer:
faust18 [17]3 years ago
7 0
1. 34.8 2. 127.2 the other ones
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Solve for x:x-7=-20<br>1)13<br>2)27<br>3)-13<br>4)-3​
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3.)-13

x-7= -20

x = -20+7

x= -13

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Al fotocopiar una credencial, primero se amplia al triple y posteriormente la copia resultante se reduce a la mitad. ¿Cual es el
ad-work [718]
Using google translate: 
When photocopying a credential, it is first enlarged to triple and subsequently the resulting copy is halved. What is the final effect on the original credential? If the credentials is a rectangle of 10 by 6 cm. What area will you have in the first photocopy? And in the second?

Original: 10 by 6 cm  ;  Area = length * width = 10 x 6 = 60 cm²

first copy: enlarged to triple
10 x 3 = 30 
6 x 3 = 18
30 x 18 = 540 cm²

second copy: halved
30 x 1/2 = 15
18 x 1/2 = 9
15 x 9 = 135 cm²


7 0
3 years ago
What number is 25℅ of 60
9966 [12]
50% is 30, it’s half of 60. 25% is the same as dividing by 4, 60/4 is 15.
7 0
3 years ago
The value of y varies directly with x. If x=4, then y=10. a. Find the constant of proportionality. b. Write an equation to repre
Lynna [10]

Answer:

aaaa

Step-by-step explanation:

In a short paragraph, describe how you would determine the amount of work needed to pull a toboggan the length of a football field. Be sure to include the equipment list and describe the measurements that you will take.

3 0
3 years ago
What does the fundamental theorem of algebra illustrate?
UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

a = 2

b = -4

c = -1

If the roots are x_{1} and x_{2}, then

x_{1} = \frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                       = \frac{4 +\sqrt{24}}{4}

                       = \frac{2+\sqrt{6} }{2}

x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

                        = \frac{4 +\sqrt{8}}{4}

                        = \frac{2-\sqrt{6} }{2}

These are the two roots of the equation.

6 0
3 years ago
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