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3 years ago

PLEASE HELP ME OUT HERE!!!! THIS IS DUE TODAY!!!!!

Mathematics

2 answers:

dolphi86 [110]3 years ago

5 0

Answer:

I'm pretty sure the answer is b

Lady bird [3.3K]3 years ago

5 0

Answer: I think is (11,4)....hope this help:)

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Abigail has $356 in her bank account. She earns simple interest on her money at a rate of 3% per year for a total of five years.

ch4aika [34]

Answer:

A. 409.4

Step-by-step explanation:

3%=10.68

10.68*5=53.4

53.4+356=409.4

3 0

3 years ago

How to estimate 5.4 x 0.1

snow_tiger [21]

I think it’s 0.54. But I’m not sure if that’s right

7 0

4 years ago

I’ll give points + brainalist for the correct answer

Triss [41]

Answer:

B: $14.50

Step-by-step explanation:

8% of $6.72 is $3.74 add that to the pay, and it will be $50.46 then 15% of that is $7.57. Add that to the previous number and you get $58.03, then divide by 4 people and you get $14.50.

5 0

3 years ago

Read 2 more answers

Bennie blinko Owns a small bookstore in Cambridge MA.Bennie is ordering some copies of Veronica Roth’s new book. Printer a sells

julsineya [31]

Divide the total price by the total number of books from each printer to find the price per book:

Printer A: $350 / 100 books = $3.50 per book

Printer B: $150 / 40 books = $3.75

Printer A has the lowest price.

7 0

4 years ago

Find the deriative dy/dx for y=x^2-2x/x^3+3

vaieri [72.5K]

Answer:

$\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

Step-by-step explanation:

So we want to find the derivative of the rational equation:

$y=\frac{x^2-2x}{x^3+3}$

First, recall the quotient rule:

$(\frac{f}{g})'=\frac{f'g-fg'}{g^2}$

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

$f=x^2-2x\\f'=2x-2$

$g=x^3+3\\g=3x^2$

So:

$\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'$

Use the above format:

$\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})$

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

8 0

4 years ago