PLEASE HELP ME OUT HERE!!!! THIS IS DUE TODAY!!!!!

Mathematics

2 answers:

dolphi86 [110]2 years ago

5 0

Answer:

I'm pretty sure the answer is b

Lady bird [3.3K]2 years ago

5 0

Answer: I think is (11,4)....hope this help:)

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A product is composed of four parts. In order for the product to function properly in a given situation, each of the parts must

svet-max [94.6K]

Answer:

P(working product) = .99*.99*.96*.96 = .0.903

Step-by-step explanation:

For the product to work, all four probabilities must come to pass, so that

P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)

where

P(Part-1) = 0.96

P(Part-2) = 0.96

P(Part-3) = 0.99

P(Part-4) = 0.99

As all parts are independent, so the formula is P(A∩B) = P(A)*P(B)

P (Working Product) = P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)

P (Working Product) = 0.96*0.96*0.96*0.99*0.99

P(Working Product) = 0.903

3 0

2 years ago

Look at The Picture Please Help!

BabaBlast [244]

Answer:

40%

Step-by-step explanation:

3/5x2=6/10

6/10x10=60/100

100-60=40

40%

5 0

3 years ago

What is the simplified form of the following expression? 7(^3 square root 2x) - 3 (^3 square root 16x) -3 (^3 square root 8x)

Pachacha [2.7K]

Answer:

The third option listed: $\sqrt[3]{2x} -6\sqrt[3]{x}\\$

Step-by-step explanation:

We start by writing all the numerical factors inside the qubic roots in factor form (and if possible with exponent 3 so as to easily identify what can be extracted from the root):

$7\sqrt[3]{2x} -3\sqrt[3]{16x} -3\sqrt[3]{8x} =\\=7\sqrt[3]{2x} -3\sqrt[3]{2^32x} -3\sqrt[3]{2^3x} =\\=7\sqrt[3]{2x} -3*2\sqrt[3]{2x} -3*2\sqrt[3]{x}=\\=7\sqrt[3]{2x} -6\sqrt[3]{2x} -6\sqrt[3]{x}$