Answer:
It is the <em><u>second one</u></em>
Step-by-step explanation:
1st option does not include the number 2 from the equation above,
and 3 and 4, you do not have to divide anywhere in the equation, so those are no possibly correct.
Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
We are given this equation :
We have to solve it for y, so we need to isolate y on the left side,
first we have 3x on the left side in addition, so when we take it to the right side we apply opposite operation that is subtract 3x
Next y is in multiplication with 5, so we apply opposite operation of multiplication that is division, so dividing right side by 5
