Answer:
- large: 40 lbs
- small: 20 lbs
Step-by-step explanation:
A system of equations can be written for the weights of the boxes based on the relationships given in the problem statement. One equation will be for the total weight of 1 large and 1 small box; the other will be for the total weight of 70 large and 60 small boxes.
Let L and S represent the weights of Large and Small boxes, respectively. The system of equations is ...
L + S = 60 . . . . . . combined weight is 60 lbs
70L +60S = 4000 . . . . weight of boxes in the truck
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We can solve this by substituting for s in the second equation.
70L +60(60 -L) = 4000
10L = 400 . . . . . . . . . subtract 3600, simplify
L = 40
S = 60 -L = 20
A large box weighs 40 pounds; a small box weighs 20 pounds.
Answer:
k = 15
Step-by-step explanation:
∵ x² - 8x + k = 0 ⇒ has two roots x1 and x2
∵ ax² + bx + c = 0 has two roots
∴ The sum of roots = -b/a and the product of them = c/a
∵ a = 1 , b = -8 and c = k
∴ x1 + x2 = -(-8)/1 = 8
∴ x1 + x2 = 8 ⇒ (1)
∵ 3x1 + 4x2 = 29 ⇒ (2)
Multiply (1) by -4
∴ -4x1 - 4x2 = -32 ⇒ (3)
Add (2) and (3)
∴ -x1 = -3
∴ x1 = 3
By substituting value of x1 in (1)
∴ 3 + x2 = 8
∴ x2 = 5
∴ The roots are 3 and 5
∴ c/a = 3 × 5 = 15 ⇒ (a = 1)
∴ c = 15
∴ k = 15
Answer:2.23607
Step-by-step explanation:
\sqrt{5} (cos(0) + i × sin (0))
\sqrt{5} (cos(π) + i × sin (π))
Missing the total payment information. Can not solve without total cost...
187 centimeters is 1.87 meters
