In probability, problems involving arrangements are called combinations or permutations. The difference between both is the order or repetition. If you want to arrange the letters regardless of the order and that there must be no repetition, that is combination. Otherwise, it is permutation. Therefore, the problem of arrange A, B, C, D, and E is a combination problem.
In combination, the number of ways of arranging 'r' items out of 'n' items is determined using n!/r!(n-r)!. In this case, you want to arrange all 5 letters. So, r=n=5. Therefore, 5!/5!(505)! = 5!/0!=5!/1. It is simply equal to 5! or 120 ways.
Answer:
a = -14
Step-by-step explanation:
a-2/3=-4. Multiply -4 by 3 to get rid of the denominator. This leaves you with a-2 = -12. Move the -2 to the other side to get a = -2-12, which simplifies to a = -14.
848 (811+37)
Using the equation
-780 + 37x44=y
-780+ 1,628= 848
Answer:
The second answer choice: ![x= \frac{x}{\ 6\pi y}](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7Bx%7D%7B%5C%206%5Cpi%20%20y%7D)
Step-by-step explanation:
Switch sides: 6πxy=z
Divide both sides by 6πy: 6πxy/6πy = z/6πy (y
0)
Then simplify: x = z/6πy, (y
0)
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