Area of the word ME = 20 square units
Solution:
Picks' Theorem:

where <em>I </em>is the interior points and <em>B</em> is the points on the boundary.
Let us first find the area of the letter M:
Number of interior points in M = 0
Number of points in the boundary = 22
Using pick's theorem,
Area of M =
Area of M = 10 square units
Now, find the area of the letter E:
Number of interior points in E = 0
Number of points in the boundary = 22
Using pick's theorem,
Area of E =
Area of E = 10 square units
Area of the word ME = Area of M + Area of E
= 10 square units + 10 square units
Area of the word ME = 20 square units
According to the Question,

<h3>From the Question,</h3>
- Initial Acceleration,a = 5 m/s²
- Force at a = 5 m/s²,f = 25 N
- Final Acceleration,A = 9 m/s²
<h3>To find</h3>
Force exerted on the object at a = 9 m/s²
We Know that,

Firstly,we need to find the mass of the object
Thus,

Now,

A = 1
b = -2
c = -3
And when you plug in and solve you'll get correct answers of x = 3 and x = -1
area = pi * r^2
here, the radius is 2 as its the diameter/2.
so the area is 4pi.
circumference = 2*pi*r.
so the circumference is 4pi as well.