- Domain:<u> List of x-values that are possible on a line</u>
- Range: <u>List of y-values that are possible on a line</u>
- Interval Notation: <u>Notation that represents the interval using the endpoints.</u> Brackets mean that the endpoint is included, parentheses means that it isn't. (e.g: (20,27] . 20 isn't included in the interval, 27 is.)
- Additional Note: <u>Open circles mean that the point is excluded, closed circles mean that the point is included.</u>
Firstly, let's look at the domain. We see an open circle at x = -6 and a closed circle at x = -1, then an open circle at x = 1 and a closed circle at x = 5. Using what we know, this means that <u>the domain is </u>
Next, let's look at the range. We see an open circle at y = -3 and a closed circle at y = 2, then we see a closed circle at y = 3 and an open circle at y = 7. Using what we know, this means that <u>the range is </u>
Answer:
w= 10
Step-by-step explanation:
hope u understand
Get all your variables on same side and solve x=-2
Answer:
15 meters
Step-by-step explanation:
The diagram of the problem is attached below in the first image.
Chords KM and LN (which is the diameter) intersect at X.
Theorem: If the diameter is perpendicular to a chord, it bisects the chord.
Therefore:
LN divides KM into equal parts of 6 meters,
Applying the theorem of intersecting chords:
KX*XM = LX*XN
6*6=3*XN
3*XN=36
XN=12
Next, we find the length of the diameter LN
LN=LX+XN
=3+12
=15 meters
The diameter of the completed circle is 15 meters.