A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
Hey there!
A quadrilateral has 360 degrees. So add all the degrees together to 360. 9x+1+5x-12+8x+61+90=360. 90 degrees is in the bottom left corner. Combine like terms. 22x+140=360. Subtract 140 from each side. 22x=220. Divide 22 on each side to get x=10. Plug in 10 for x in angle D. 5(10)-12=38. The measure of angle D is 38 degrees.
I hope this helps!
Answer:
the triangle is right
Step-by-step explanation:
The Pythagorean theorem dictates that a^2 +b^2=c^2
6^2+8^2=10^2
36+64=100
100=100
100+(34-(4+2)*3)/4
=100+(34-6*3)/4
=100+(34-18)/4
=100+16/4
=116/4
=29
29 is the answer
Answer:
I think the answer is A
Step-by-step explanation:
So sorry if the answer is incorrect
