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Mrac [35]
3 years ago
6

Which quantity is proportional to 15⁄3? Check all that are true. 5⁄1 12⁄4 75⁄15 30⁄4 45⁄9

Mathematics
1 answer:
Scrat [10]3 years ago
7 0
75/15 is one of them. Not sure about the rest
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The difference of a number times 2 and 3 equals 8.
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I think the answer is 2 but I'm not sure
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2 years ago
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Vo.
LiRa [457]

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The answer is b and e

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Which of the sets of equations represent the two lines graphed?
Oksi-84 [34.3K]

Answer:

B) y = x + 2 and y = -x - 4

Step-by-step explanation:

Let the equation of a straight line with x-intercept 'a' and y-intercept 'b' be

\frac{x}{a}  +  \frac{y}{b}  = 1

The line with positive slope has x-intercept a=-2 and y-intercept b=2.

Its equation is:

\frac{x}{ - 2}  +  \frac{y}{2}  = 1

Multiply through by 2

- x + y = 2

Solve for y,

\boxed {y = x + 2}

For the line with a negative slope,

the x-intercept is a=-4 and the y-intercept is b=-4

Its equation is

\frac{x}{ - 4}  +  \frac{y}{ - 4}  = 1

Multiply through by -4

x + y =  - 4

Solve for y

\boxed {y =  - x - 4}

4 0
2 years ago
A. 55<br> b. 70<br> c. 110<br> d. 125
morpeh [17]

Answer:

b

Step-by-step explanation:

7 0
2 years ago
Find the standard equation of the circle with center (5, -3
Mrac [35]

Answer:

○ C

Explanation:

Accourding to one of the circle equations, \displaystyle (x - h)^2 + (y - k)^2 = r^2,the centre of the circle is represented by \displaystyle (h, k).Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:

Pythagorean Theorem

\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = r^2 \hookrightarrow 36 + 64 = r^2 \hookrightarrow \sqrt{100} = \sqrt{r^2} \\ \\ \boxed{10 = r}

Sinse we are dealing with <em>length</em>, we only desire the NON-NEGATIVE root.

Distanse Equation

\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-5 - 3]^2 + [3 + 3]^2} = r \hookrightarrow \sqrt{[-8]^2 + 6^2} = r \hookrightarrow \sqrt{64 + 36} = r; \sqrt{100} = r \\ \\ \boxed{10 = r}

Sinse we are dealing with <em>distanse</em>, we only desire the NON-NEGATIVE root.

I am joyous to assist you at any time.

5 0
2 years ago
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