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4 years ago

Which quantity is proportional to 15⁄3? Check all that are true. 5⁄1 12⁄4 75⁄15 30⁄4 45⁄9

Mathematics

1 answer:

Scrat [10]4 years ago

7 0

75/15 is one of them. Not sure about the rest

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PLEASE HELP QUICKLY!!! Use the following image to answer the questions below:

AlexFokin [52]

I think it’s because they are opposite so Yh sos if it’s wrong

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3 years ago

10.The function f(x) is shown below:

Tom [10]

A. -f(1)=1,f(2)=2,f(n)=2f(n-1)f(n-2);n>2

7 0

3 years ago

What is the factored form of x^2-x-2

lisov135 [29]

Answer:

(x-2),(x+1)

Step-by-step explanation:

5 0

3 years ago

1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c

prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

$P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}$

a) One randomly selected person preferes aisle seat with probability

$\dfrac{153}{403}$

b) Two randomly selected people both prefer aisle seat (with replacement) is

$\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}$

c) Two randomly selected people both prefer aisle seat (without replacement) is

$\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}$

8 0

3 years ago

How did I I get this wronggggggg

SIZIF [17.4K]

Answer:

mhmmm well i don't know what you got wrong but it was prob cus u didnt sum wrong or wasn't paying attention to what you were doing. Hope this helpss have a safe and joyful holiday

Step-by-step explanation:

8 0

3 years ago