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3 years ago

14

URGENT PLS ANSWER IM STRUGGLING !!

2 answers:

solong [7]3 years ago

6 0

What she said is correct the y intercept

Goshia [24]3 years ago

4 0

Answer:

D: x-intercept is (10,0); y-intercept is (0,-5)

Step-by-step explanation:

When y=0 that is your x-intercept.

When x=0 that is your y-intercept.

Remember also that coordinate pairs are written as (x,y). Your answer is almost right, but it was written as (y,x) instead.

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i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

2 years ago

AYLIN AHORRO 200 MAS SU HERMANO Y RECIBIERON CADA UNO 2400 DE BECA CON SUS AHORROS Y SUS BECAS LES ALCANZA JUSTO PARA COMPRAR EL

stich3 [128]

What’s the language is this

6 0

2 years ago

Read 2 more answers

Convert from fraction to decimal 7/9

Fudgin [204]

Answer:

0.77777778

Step-by-step explanation:

4 0

2 years ago

A leaky water faucet loses 0.25 liter of water

Viefleur [7K]

Answer:

3 liters.

Step-by-step explanation:

You can write the problem as an equation.

f(x)=0.125x

Where x is the number of hours. The 0.125 is how many liters the faucet loses in 1 hour. Then, just plug in 24.

0.125*24=3

5 0

3 years ago

Carla and Brandon are members of two different magazine programs where any magazine ordered is the same price, regardless of the

svp [43]

C because 9.44 divided by 4 is 2.46

5 0

2 years ago