Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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Answer: Just drag each box over to the other box
Step-by-step explanation:
just how i said
I can not set up a 2 way table online but what they want is a collom of the information neatly laid out...
With the 9th graders in one collom and the 10th graders in the other
like this
9th grader 10th grader
# of students 32 40
# of participated 32 18
Draw this out with lines and it will be correct.
I hope this helps GOOD LUCK...this is tough math for a middle schooler.
Step-by-step explanation:
step one: *multiply the negative 9 with the 5j.
which which will come out to be -45j
step 2: now now multiply the -9 with the k. which it comes out to be negative 9k.
step 3: -45j + -9k
