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3 years ago

Expand. Put the boxes in order to show the correct expansion.

Mathematics

1 answer:

BARSIC [14]3 years ago

7 0

Answer:

Box-4 → (+)

Step-by-step explanation:

To find the value in the 4th box, we will expand the given logarithmic expression.

log₄x⁵y³ = log₄x⁵ + log₄y³

= 5log₄x + 3log₄y

Therefore, each box will have the values as,

Box-1 → 5

Box-2 → log₄

Box-3 → x

Box-4 → (+)

Box-5 → 3

Box-6 → log₄

Box-7 → y

There is the (+) sign in Box-4.

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What is 832.248 rounded to the nearest tenth? A. 830 B. 832.2 C. 832.25 D. 832.3

OleMash [197]

Hi there.

To start, we have to understand where the ten the place is.

Hint: it's 1 place behind the decimal point.

Now we need to know what numbers behind the tenths place make it round up or down.

If the number behind it is 4 or under, round down.

5 & up, round up.

In this case, 830.248 has 2 numbers behind the decimal, so we have to round those THEN the 2 in the tenths place.

830.25 to 830.3

Your answer is D. 830.3

I know this was lengthy, sorry. Just wanted to explain :p

4 0

3 years ago

A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the

Alexus [3.1K]

4x+6y=56 and y=4x can be used to determine the number of small cars rented and the number of large cars rented, where x represents number of small cars and y represents number of large cars.

Step-by-step explanation:

Number of people hold by small cars = 4

Number of people hold by large cars = 6

Let,

Number of small cars = x

Number of large cars = y

The students rented 4 times as many large cars as small cars,

y = 4x Eqn 1

which altogether can hold 56 people.

4x+6y=56 Eqn 2

4x+6y=56 and y=4x can be used to determine the number of small cars rented and the number of large cars rented, where x represents number of small cars and y represents number of large cars.

Keywords: linear equations, addition

Learn more about linear equations at:

#LearnwithBrainly

6 0

3 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is

Anastaziya [24]

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, $\overline x$ = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

$t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}$

We get;

$t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712$

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t = 2.166587

The p-value is obtained using an online source as p(t ≤ -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

3 0

2 years ago

Find all the real cube roots of 0.000064

prohojiy [21]

$\sqrt[3]{0.000064}= \sqrt[3]{ \frac{64}{1,000,000} }= \sqrt[3]{ \frac{4^3}{100^3} }= \sqrt[3]{ (\frac{4}{100})^3 }= \frac{4}{100}=0.04$

6 0

3 years ago

Read 2 more answers

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as

mamaluj [8]

Answer:

The farmer have at first 202 chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be $x.$

And, the ducks be $y.$

As, the farmer had twice as many chickens as ducks on his farm.

So, $x=2y$ ......(1)

As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.

According to question:

$x-166=(y-29)\times \frac{1}{2}$

$x-166=\frac{y-29}{2}$

Substituting the value of $x$ from equation (1) we get:

$2y-166=\frac{y-29}{2}$

By cross multiplying we get:

$4y-332=y-29$

Adding both sides 332 we get:

$4y=y+303$

Subtracting both sides by $y$ we get:

$3y=303$

Dividing both sides by 3 we get:

$y=101.$

Now, to get the number of chickens substituting the value of $y$ in equation (1):

$x=2y\\\\x=2\times 101\\\\x=202.$

Therefore, the farmer have at first 202 chickens.

7 0

3 years ago