Answer:
Check boxes 3, 4, 6, and 8.
Step-by-step explanation:
We have the equation:
And we want to select all equations that are perpendicular to the above equation.
Remember that perpendicular lines have slopes who are negative reciprocals of each other.
Therefore, the slope of our equations must be the negative reciprocal of -3.
The negative reciprocal of -3 is 1/3. We flipped -3 to -1/3, and then multiplied by a negative.
Therefore, any equation with a slope of 1/3 is perpendicular to our original line.
Therefore, we will check boxes 3, 4, 6, and 8.
Part (a)
Plug in y = 0 and solve for x. Use the zero product property
y = x(x+3)(x-2)
0 = x(x+3)(x-2)
x(x+3)(x-2) = 0
x = 0 or x+3 = 0 or x-2 = 0 .... zero product property
x = 0 or x = -3 or x = 2
The three roots or zeros are x = 0 or x = -3 or x = 2
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Part (b)
The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.
Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.
So that's why the graph does <u>not</u> match with the function in part (a)
(x+5)/4=1/2
first get rid of the fraction
multiply both sides by 4
x+5=2
subtract 5
x=-3
(2x+1)/(4x-1)=2/3
get rid of the fractions,
multiply both sdies by (4x-1)(3)
(2x+1)(3)=(2)(4x-1)
distribute
6x+3=8x-2
subtract 6x form both sdies
3=2x-2
add 2
5=2x
divide by 2
5/2=x
I wish I could follow you
Nice to come across this though
