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BabaBlast [244]
4 years ago
9

1. In ABC , m (a) Find the value of x. (b) Find the measure of . Show your work.

Mathematics
1 answer:
777dan777 [17]4 years ago
7 0
I hope this helps you

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For each hour he babysits, Anderson earns $1 more than half of Carey’s hourly rate. Anderson earns $6 per hour. Which equation c
balu736 [363]
Carey earns c hourly
Anderson earns $6 hourly which is also 1+ c/2So, 6=1+c/2      12=2+cc=$10
Carey earns $10 hourly<span>
</span>
8 0
3 years ago
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a taxi service charges $2.40 for the first mile of a ride and $1.40 for every additional mile. linda planned to give a $2 tip fo
Grace [21]

Answer:

5 miles

Step-by-step explanation:

2 as a baseline then add 2.40 for first mile which then comes up to 4.40. 4.40 plus 1.40 = 5.80 plus 1.40 = 7.20 plus 1.40 = 8.60 plus 1.40 = 10. then we count the amount of 1.40's we added which was 4. and then we account for the first mile so there we have 5 miles

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3 years ago
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If you know him i love ill give out brainliest
tiny-mole [99]

Answer:

Lucifer

Step-by-step explanation:

But a lot thinner

5 0
3 years ago
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WILL GIVE BRAINLIEST
Mnenie [13.5K]

Answer:

C

Step-by-step explanation:

Given the 2 equations

3x + 4y = 8 → (1)

y - 5x = 2 ← rewrite as

- 5x + y = 2 → (2)

Multiplying (2) by - 4 and adding to (1) will eliminate the y- term

20x - 4y = - 8 → (3)

Add (1) and (3) term by term to eliminate y

23x + 0 = 0

23x = 0 , then

x = 0

Substitute x = 0 into either of the 2 equations and solve for y

Substituting into (1)

3(0) + 4y = 8

4y = 8 ( divide both sides by 4 )

y = 2

solution is (0, 2 )

That is the lines intersect once at (0, 2 )

6 0
3 years ago
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Find how many solutions there are to the given equation that satisfy the given condition. X1 + x2 + x3 = 22, each x; is a positi
DiKsa [7]

Answer:

Step-by-step explanation:

Given that there are three variables satisfying the equation

X1 + x2 + x3 = 22

Here each x is given to be a positive integer

i.e. solution set for each of the variable can be any integer from 1 to 20 at most.(because if two other integers are 1 each third has to be 20)

Hence solution set can be of the form

(x1,x2,x3) =(1,1,22) (1,2,21) (1,3,20).....

=(2,1,19) (2,2,18),...\\=(3,1,18) (3,2,17),....\\...\\...\\=(20,1,1)

If x1 =1, there are 20 solution sets

If x1 =2,there are 19

...

If x1 =20 there is 1 set

Hence total solutions can be= 20+19+...+1\\=\frac{20(21)}{2} =210

6 0
3 years ago
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