The following dot plot represents a random sample of elementary students and the number of children that live in their home.

State the domain of the following : a. y = √ x + 1 /√ 25 − x^2 b. f(x) = (√ 1 − x ) ln x

almond37 [142]

Answer:

a.) -1 < x < 5

b.) x <= 1

Step-by-step explanation: Domain is the independent variable (x).

For both question a and b, make sure that the number under the square root does not end up being negative. And the denominator of the fractional number is not equal to zero when variable x is being substituted for any value.

a.) y = √ x + 1 /√ 25 − x^2

Domain : -1 < x < 5

That is the minimum value for x is 0 and the maximum value is 4

b. f(x) = (√ 1 − x ) ln x

Domain : x <= 1

That is, x is less than or equal to 1

The maximum value for x is 1. x can be

1, 0, -1, -2, -3, ..........

8 0

3 years ago

Help me to answer this

Anton [14]

Answer:

Mode - 2

Range - 11

Seven scored 1 time

Median - 2

Total - 19

4 0

3 years ago

Read 2 more answers

Which best describes the required locus? all points in a plane equidistant from two given points in the plane.

zavuch27 [327]

Answer:

C.

Step-by-step explanation:

The line that is a perpendicular bisector of the segment connecting the two points.

6 0

3 years ago

Read 2 more answers

PLEASE HELP RIGHT NOW!!! *** I WILL GIVE BRAINLIEST ***

bija089 [108]

Two Correct choice:

Step 5: E

Step 2: B

//But not sure.

7 0

3 years ago

The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg

amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

$\\ 0.239 =\frac{239}{1000}\;or\;23.9\%$

Step-by-step explanation:

From the question, we have the following information:

The distribution for protein requirement is normally distributed.
The population mean for protein requirement for adults is $\\ \mu= 0.65 gP*kg^{-1}*d^{-1}$
The population standard deviation is $\\ \sigma =0.07 gP*kg^{-1}*d^{-1}$

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about the proportion of the population that has a requirement less than $\\ x = 0.60 gP*kg^{-1}*d^{-1}$ .

For answering this, we need to calculate a z-score to obtain the probability of the value x in this distribution using a standard normal table available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

$\\ z = \frac{x - \mu}{\sigma}$

For the given parameters, we have:

$\\ z = \frac{0.60 - 0.65}{0.07}$

$\\ z = -0.7142857$

<h3>Determining the probability</h3>

With this value for z at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is symmetrical.

Tables have values for z with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the standard normal table gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

$\\ P(x$

$\\ P(x$ (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

$\\ 0.239 =\frac{239}{1000}\;or\;23.9\%$

See the graph below. The shaded area is the region that represents the proportion asked in the question.

5 0

3 years ago