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trasher [3.6K]
3 years ago
8

Describe the alignment of Earth, the moon, and the sun during spring tides, when tides are most extreme

Geography
1 answer:
natima [27]3 years ago
3 0
I don’t know the answer to that sorry.
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True

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Earth is closet to the sun at a point called
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Flatirons - Wind River Mountains, WY. The Problem 1 polygon highlights a single flatiron in a tilted region composed of numerous
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They are dipping in the north eastern direction.

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Rock layers are correlated if they both contain the same ____.
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Read 2 more answers
Suppose 0 is an angle in the standard position whose terminal side is in Quadrant IV and cot0= -6/7 Find the exact values of the
Sergio039 [100]
<h2>\sin \theta=\dfrac{p}{h} =\dfrac{-7}{\sqrt{85} }, \cos \theta=\dfrac{b}{h} =\dfrac{6}{\sqrt{85}}, \tan \theta=\dfrac{p}{b} =\dfrac{-7}{6},</h2><h2>\sec \theta=\dfrac{h}{b} =\dfrac{\sqrt{85} }{6} and \csc \theta=\dfrac{h}{p} =\dfrac{-\sqrt{85}}{ 7}</h2>

Explanation:

Given,

\cot \theta= \dfrac{-6}{7}

To find, the exact values of the five remaining trigonometric functions of \theta = ?

We know that,

\cot \theta= \dfrac{-6}{7}=\dfrac{b}{p}

Where, b = base and p = perpendicular

By Pythagoras's theorem,

Hypotaneous, h=\sqrt{p^2+b^2}

=\sqrt{(-6)^2+7^2}=\sqrt{36+49} =\sqrt{85}

In IVth quadrant,

\cot \theta and \sec \theta are positive.

\sin \theta=\dfrac{p}{h} =\dfrac{-7}{\sqrt{85} }, \cos \theta=\dfrac{b}{h} =\dfrac{6}{\sqrt{85}}, \tan \theta=\dfrac{p}{b} =\dfrac{-7}{6},

\sec \theta=\dfrac{h}{b} =\dfrac{\sqrt{85} }{6} and \csc \theta=\dfrac{h}{p} =\dfrac{-\sqrt{85}}{ 7}

7 0
3 years ago
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