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IgorLugansk [536]
3 years ago
5

Which of the following is NOT true about a space-based internet system? * Data is transmitted in the form of electromagnetic rad

iation. Signals travel faster through space than through fiber-optic cables. No ground equipment is needed to access the internet. The network is made of many satellites organized in a grid pattern
Physics
2 answers:
AURORKA [14]3 years ago
4 0

Answer:

B

Explanation:

Oksanka [162]3 years ago
3 0

Answer:

A Data is transmitted in the form of electromagnetic radiation.

B Signals travel faster through space than through fiber-optic cables.

C No ground equipment is needed to access the internet.

D The network is made of many satellites organized in a grid pattern.

Explanation:

THose are the options

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From one object's center of gravity to the other's
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Small, solid pieces of material that come from rocks or living things are called ____
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It will be sediment, that's the only thing can be in a rock and it's a living thing. Sediment is part of a rock so that's your answer this is a 7th grade question not that hard I'm in the 5th grade no officence but enjoy your answer
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A reaction taking place in a container with a piston-cylinder assembly at constant temperature produces a gas, and the volume in
djverab [1.8K]

Answer:

60.4 J

Explanation:

The work done by the gas is given by:

W=p(V_f-V_i)

where

p is the gas pressure

V_f is the final volume of the gas

V_i is the initial volume

We must convert all the quantities into SI units:

p=860 torr \cdot \frac{1.013\cdot 10^5 pa}{760 torr}=1.146\cdot 10^5 Pa

V_i = 127 mL = 0.127 L = 0.127 dm^3 = 0.127 \cdot 10^{-3}m^2

V_f = 654 mL = 0.654 L = 0.654 dm^3 = 0.654 \cdot 10^{-3}m^2

So the work done is

W=(1.146\cdot 10^5 Pa)(0.654\cdot 10^{-3} m^3-0.127\cdot 10^{-3} m^3)=60.4 J

4 0
3 years ago
The amount of force required to deform a spring is _____.
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The first one, directly proportional to the length that the spring is stretched.
8 0
4 years ago
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A seagull flying horizontally over the ocean at a constant speed of 2.60 m/s carries a small fish in its mouth. It accidentally
Ivenika [448]

(a) +2.60 m/s

The motion of the fish dropped by the seagul is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, at constant speed

- a vertical motion, at constant acceleration (acceleration of gravity, g=-9.8 m/s^2, downward)

In this part we are only interested in the horizontal motion. As we said the horizontal component of the fish's velocity does not change, therefore its value when the fish reaches the ocean is equal to its initial value, which is the speed at which the seagull was flying (because it was flying horizontally):

v_x = +2.60 m/s

(b) -17.2 m/s

The vertical component of the fish's velocity instead follows the equation:

v_y = u_y +gt

where

u_y = 0 is the initial vertical velocity, which is zero

g=-9.8 m/s^2 is the acceleration of gravity

t is the time

Since the fish reaches the ocean at t = 1.75 s, we can substitute this time into the formula to find the final vertical velocity:

v_y = 0+(-9.8)(1.75)=-17.2 m/s

where the negative sign indicates the direction (downward).

(c)

The horizontal component of the fish's velocity would increase

The vertical component of the fish's velocity would stay the same.

As we said from part (a) and (b):

- The horizontal component of the fish's velocity is constant during the motion and it is equal to the initial velocity of the seagull -> so if the seagull's initial speed increases, the horizontal velocity of the fish will increase too

- The vertical component of the fish's velocity does not depend on the original speed of the seagull, therefore it is not affected.

4 0
3 years ago
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