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tester [92]
2 years ago
10

In an atom that has an electron configuration of 1s^2 2s^2 wp^5, what is the total number of electrons in its sublevel of highes

t energy?
Physics
1 answer:
frutty [35]2 years ago
8 0

In an atom that has an electron configuration of 1s^2 2s^2 2p^3. The total number of electrons in its sublevel of highest energy is 3.

Electronic configuration represents the number of electrons in the excited state or in the subshells of an element.

1s^2 2s^2 2p^3 is the electronic configuration of nitrogen i.e. N7.

The atomic number of nitrogen is 7 and the atomic mass is 3. Hence, the electrons are in the 's' and 'p' subshells of the main shell.

This electronic configuration shows that nitrogen is in an exciting oxidation state and has 3 electrons in its highest energy level.

If you need to learn more about electron configuration click here:

brainly.com/question/26084288

#SPJ4

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Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm
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Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?

Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.  

(a) What is the electric potential at point a due to q1 and q2?  

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Answer:

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r = 5cm = 0.05m

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v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m

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Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when i
LenaWriter [7]

The given question is incomplete. The complete question is as follows.

You throw a ball vertically upward, and as it leaves your hand, its speed is 26.0 m/s.

(a) How high (in m) does it rise above the level where it leaves your hand?

(b) How long (in s) does it take to reach its highest point?

(c) How long (in s) does the ball take to return to the level where it left your hand after it reaches its highest point?

(d) Assume that the upward direction is positive and the downward direction is negative. What is the ball's velocity (in m/s) when it returns to the level where it left your hand? (Indicate the direction with the sign of your answer.)

Explanation:

(a) For maximum height, the formula will be as follows.

           v^{2} = u^{2} + 2as

                 a = v^{2} - 2gh

or,                 h = \frac{v^{2}}{2g}

                        = \frac{(26)^{2}}{2 \times 9.8}

                        = \frac{676}{19.6}

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            v = u + at

or,           v - gt = 0

                 t = \frac{v}{g}

                   = \frac{26}{10}

                   = 2.6 sec

Therefore, it will take 2.6 sec to reach its highest point.

(c)  Time taken by the ball to ascent is equal to the time it has taken to descent.

Therefore, time taken by the ball to return to the level where it left your hand after it reaches its highest point? is also 2.6 sec.

(d)  Speed of the ball will be 26 m/s in the downward direction. Hence, the velocity will be -26 m/s.

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