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Talja [164]
3 years ago
10

Identify the following fractions as either proper or improper. 8. 14⁄ 15

Mathematics
1 answer:
nalin [4]3 years ago
4 0

Answer:

proper I believe if I'm wrong sorry

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Island A is 160 miles from island B. A ship captain travels 220 miles from island A and then finds that he is off course and 200
Angelina_Jolie [31]

Answer:

=135.53°

Step-by-step explanation:

The bearing that the captain should turn is the angle difference between the two islands from the position of the ship.

Let C be the position of the ship, then

AB is c=160

AC is b=220

BC is a=200

We use the cosine rule as follows:

c²=a²+b²-2ab Cos C

160²=200²+220²-2×200×220 Cos C

25600=88400-88000Cos C

88000 Cos C=88400-25600

88000Cos C=62800

Divide both sides by 88000.

Cos C=62800/88000

=0.7136

C=44.47°

He should turn (180°-44.47°)=135.53°

3 0
3 years ago
Which angle(s) is/are co-terminal to
Olenka [21]
D is the right answer all of the above
3 0
2 years ago
Read 2 more answers
A bodybuilder is 6ft 4in tall and has a body mass index of 27.6. How much does he weight?
balu736 [363]
To determine the weight of the bodybuilder and since we are given the BMI or the boddy mass index and the height, it would be best to use these values. BMI is a measurement that is used to scaled body fat based in the weight and the height of adult women and men. It is calculated by the equation as follows:

BMI = 703 (mass in lb / height in inches^2)

Given: 
height = 6ft 4in
BMI = 27.6

Solution:
height = 6 ft ( 12 in /1 ft ) + 4 in = 76 in

BMI = 703 (mass in lb / height in inches^2)
27.6 = 703 (mass in lb / 76^2)
mass = 226.77 lb or  103.08 kg
4 0
4 years ago
Prove that the limit x tends to 1 (2x^4-6x^3+x^2+3)÷(x-1)=-8
elixir [45]
First note that if x\neq1, you have

\dfrac{2x^4-6x^3+x^2+3}{x-1}=2x^3-4x^2-3x-3

Now, you're looking for \delta>0 such that for any \varepsilon>0, you have

|x-1|

Note that you can divide through the left side of the \varepsilon inequality by x-1 once more:

\dfrac{2x^3-4x^2-3x+5}{x-1}=2x^3-2x-5\implies 2x^3-4x^2-3x+5=(x-1)(2x^2-2x-5)

So it follows that you need to find an appropriate \delta that will guarantee

|(x-1)(2x^2-2x-5)|=|x-1||2x^2-2-5|

For the moment, let's fix \delta=1. Then by this assumption, we have

|x-1|

From this we get

\implies0
\implies0
\implies0
\implies-5
\implies1

where the upper bound is what we care about. With this assumption, we then get that

|x-1||2x^2-2-5|

which suggests that \delta can be taken to be either the smaller of 1 or \dfrac{\varepsilon}5, or \delta=\min\left\{\dfrac{\varepsilon}5,1\right\}, to guarantee that the function gets arbitrarily close to -8.
5 0
3 years ago
Which of the following expressions will find the sum of interior angles of a polygon with 14 sides?
Effectus [21]
Central angle of polygon with 14 sides is:
a = 360/14

that means that interior angle is:
b = (180 - 360/14)/2

because sum of angles in a triangle is 180.
each triangle has 2*b angles and there are 14 angles. so sum of all those angles is:
2*b*14 = (180-360/14)/2*14*2 = 180*14-360 = 180*14 - 2*180 = 180*(14-2)

Answer is second option.
4 0
3 years ago
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