The present value of the loan will be = R36,250
<h3>Calculation of the present value</h3>
The principal capital (P) = R25 000
Interest rate for the payment (R)= 7.5%
Time for the payment (T)= 6 years
Therefore simple interest = P×T×R/100
= 25,000×6×7.5/100
= 250×6×7.5
= R11,250
The present value of the loan will be;
= 25,000 + 11,250
= R36,250
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Answer:
The answer is below
Step-by-step explanation:
A linear graph has an equation of the form:
y = mx + b,
where y and x are variables, m is the slope (rate of change) of the graph and b is the y intercept (value of y when x is 0).
Given that:
2x -2y = 4 , 3x + 2y = 6
The matrix form of the equation is:
AX = B
![A=\left[\begin{array}{cc}2&-2\\3&2\end{array}\right] ,X=\left[\begin{array}{c}x\\y\end{array}\right] ,B=\left[\begin{array}{c}4\\6\end{array}\right] \\\\Therefore:\\\\\left[\begin{array}{cc}2&-2\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}4\\6\end{array}\right] \\\\\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{cc}2&-2\\3&2\end{array}\right]^{-1} \left[\begin{array}{c}4\\6\end{array}\right] \\\\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%20%2CX%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%2CB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D4%5C%5C6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CTherefore%3A%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D4%5C%5C6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%5E%7B-1%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D4%5C%5C6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C)