Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward. So, y-5 = (x-2)² Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum) The domain (x- value) is all Real { x|x = -∞ to x=+∞} The Range (y-value) is all y ≥ 5
It will be 8.5 because if you add a zero at the end of 8.5 that will be 8.50 and 8.50 is half of 9 and 9 is closes to the solution sooo.... thats what i pick
