<u>Given</u>:
Given that the isosceles trapezoid JKLM.
The measure of ∠K is 118°
We need to determine the measure of each angle.
<u>Measure of ∠L:</u>
By the property of isosceles trapezoid, we have;
Thus, the measure of ∠L is 62°
<u>Measure of ∠M:</u>
By the property of isosceles trapezoid, we have;
Substituting the value, we get;
Thus, the measure of ∠M is 62°
<u>Measure of ∠J:</u>
By the property of isosceles trapezoid, we have;
Substituting the value, we get;
Thus, the measure of ∠J is 118°
Hence, the measures of each angles of the isosceles trapezoid are ∠K = 118°, ∠L = 62°, ∠M = 62° and ∠J = 118°
Max height is the vertex
convert to vertex form (y=a(x-h)^2+k) by completeing the square
h(t)=-16(t²-4t)+80
h(t)=-16(t²-4t+4-4)+80
h(t)=-16((t-2)²-4)+80
h(t)=-16(t-2)²+64+80
h(t)=-16(t-2)²+144
vertex is (2,144)
at t=2, the height is 144
max height is 144ft
Answer:
Mark point E where the circle intersects segment BC
Step-by-step explanation:
Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.
Bill's next step is to mark point E, so he can use it as the center of one of the circles just described.
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<em>Comment on Bill's "technology"</em>
In the technology I would use for this purpose, the next step would be "select the angle bisector tool."
There are 100229 threes in the first million digits in pi.
Answer:
m = 56
Step-by-step explanation:
1/2m - 5 = 23
add 5 to both sides
1/2m - 5 + 5 = 23 + 5
1/2m = 28
multiply both sides by 2
1/2m(2) = 28(2)
m = 56
