circle: x2+ y2 = 2
parabola: y = 2x2 – 3
The standard form of equation of circle is:
( x – h )^2 + ( y – k )^2 = r^2
We are given the equation x^2 + y^2 = 2.
Where h and k are the x and y coordinates of the center.
Basing on the standard equation, the center is at (0 , 0) and r =
The standard form of equation of parabola with the axis of symmetry parallel to the y-axis is:
(x - h)^2 = 4p (y - k)
Rearranging the given equation into this form:
x^2 = (½) y + 3/2
x^2 = ½ (y + 3)
Since 4p is positive value, therefore the parabola is opening up. The vertex is located at (0 , -3).
<span>Answer: circle with its center at (0, 0) and a radius of </span>