2 years ago

The first term of a gemotetric sequence is -15 and the common ratio is 6 What is the twelfth term of the sequence

Mathematics

1 answer:

nikklg [1K]2 years ago

8 0

Answer:

Step-by-step explanation:

a₁₂ = a₁r¹²⁻¹ = -15×6¹¹

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Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

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In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

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Where

$TV = 6$

and

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Take square roots

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So:

$cos V= \frac{TV}{UV}$

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