All categories

3 years ago

The first term of a gemotetric sequence is -15 and the common ratio is 6 What is the twelfth term of the sequence

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

Step-by-step explanation:

a₁₂ = a₁r¹²⁻¹ = -15×6¹¹

You might be interested in

In the souvenir shop, Gary finds a shirt and a key chain he would like to buy. The shirt costs $13.75 and the key chain costs $2

Firlakuza [10]

Answer:

$16.08

Step-by-step explanation:

13.75+2.33=16.08

3 0

3 years ago

What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2? (5 points)

tiny-mole [99]

The third choice is appropriate.
an = 5 - 3(n - 1); all integers n ≥ 1

_____
This equation follows the form for the general term of an arithmetic sequence.
an = a1 + d(n - 1)
where a1 is the first term (corresponding to n=1), and d is the common difference. From the problem statement, a1 = 5 and d = 2 - 5 = -3.

6 0

3 years ago

Factor 3y3 – 9y2<br> The factored polynomial is

allochka39001 [22]

Answer:

Factor 3y23y2 out of 3y33y3.

3y2(y)−9y23y2(y)-9y2

Factor 3y23y2 out of −9y2-9y2.

3y2(y)+3y2(−3)3y2(y)+3y2(-3)

Factor 3y23y2 out of 3y2(y)+3y2(−3)3y2(y)+3y2(-3).

3y2(y−3)

Step-by-step explanation:

mark me the brainliest please

4 0

3 years ago

What should i know about algebra 1 before i start

Contact [7]

Answer:nothin much

Step-by-step explanation:

8 0

3 years ago

Is the answer a, b, c, or d.

ale4655 [162]

The correct answer is d.

We have the following system of linear equations:

(I) $4x+7y=-14$
(II) $8x+5y=8$

Let's use the elimination method, then let's multiply the equation (1) $\times(-2)$ and subtracting (I) and (II):

(I) $-2(4x+7y)=-2(-14)$
∴ $-8x-14y=28$

(I) $-8x-14y=28$
(II) $8x+5y=8$
____________________
(III) $-9y=36$

∴ $y=-4$

We can find the value of x by substituting y either in (I) or (II). Thus, from (I):

$4x+7(-4)=-14$
∴ $4x-28=-14$
∴ $4x=14$
∴ $x=\frac{14}{4}$
∴ $\boxed{x=\frac{7}{2}}$

Let's substitute the values of x and y into (I) and (2)

(I) $4(\frac{7}{2})+7(-4)=14-28=-14$
(II) $8(\frac{7}{2})+5(-4)=28-20=8$

Finally the answer is:

$\boxed{x=\frac{7}{2} \rightarrow x= 3 \frac{1}{2}}$

4 0

3 years ago