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ch4aika [34]
3 years ago
5

Please help me on this

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer: option a.

Step-by-step explanation:

Given the expression \sqrt{8^{17}}, you need to remember:

The Product of powers property:

a^m*a^n=a^{(m+n)}

The Power of a power property:

(a^m)^n=a^{mn}

And:

\sqrt[n]{a^n}=a

Therefore, as the index of the radical is 2, you can rewrite 8^{17} as:

8^{17}=8^{16}*8

Rewrite this and simplify. Then:

 =\sqrt{8^{17}}

=\sqrt{8^{16}*8}=\sqrt{8^{16}}\sqrt{8}=\sqrt{(8^{8})^2}\sqrt{8}=8^8\sqrt{8}

 

This matches with the option a.

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when 0 on the bottom is zero

Step-by-step explanation:

that mean there would be no whole nor a proper quotient

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The figure is made from squares of different sizes.Find the area of A if the side of each of the two indentical smallest square
Temka [501]

Answer:

The area of square A is 256 cm²

Step-by-step explanation:

  • <em>The four sides of a square are equal in length</em>
  • <em>Area of a square = side × side</em>

In the given figure

∵ The sides of the square E = 2 cm each

∵ The sides of the square F = 2 cm each

∵ The side of square D is the sum of the sides of squares E and F

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∴ The sides of square B = 6 + 2 + 2= 10 cm each

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3 0
3 years ago
A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the averag
ahrayia [7]

Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:

X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

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A and b are the correct answers
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