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Darina [25.2K]
3 years ago
9

5 ft

Mathematics
2 answers:
tresset_1 [31]3 years ago
6 0

Answer:

360 feet

Step-by-step explanation:

5 times 6 equals to 30.

30 times 12 equals 360.

Rom4ik [11]3 years ago
3 0

Answer:

Assuming this is a rectangular prism the surface area would be 324ft^2.

Step-by-step explanation:

Surface Area = 2(lw + lh + wh).

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Wilmer already has 214 cards. he needs to collect 334 cards. he plans to collect 8 cards each day. find the minimum number of da
Wittaler [7]
The answer is 15 days.

The first step you need to take is to subtract the amount of cards he has from the amount of cards he needs. So 334 (needs) - 214(has) = 120 cards he still needs. So he is collecting 8 cards a day. In order to find out how many days it will take to collect the 120 cards, we need to divide 120 by 8. 120 divided by 8 is 15. So it will take 15 days collecting 8 cards a day in order to reach the 120 cards he still needs to collect.
3 0
3 years ago
translate this equation. 126 is the product of goran's score and 7..use the variable g to represent gorans score
FromTheMoon [43]

7g = 126 is the translation

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3 years ago
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What is the slope of the line through the points (-3, 5) and (4, 5)?
Natasha_Volkova [10]

Answer:

Slope: 0

Step-by-step explanation:

(-3,5) (4,5)

y2-y1/x2-x1

5-5/4+3=0/7

0/7 simplifies to 0.

So the slope of the line (-3,5) (4,5) is 0.

Hope this helps! ;)

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3 years ago
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If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

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The square of the product of 4 and a number.
aleksley [76]

the square root of 4x


\sqrt{4x}

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