here we have 3X to 5 seventh power in radical form
we need write this in radical form we knwo that 
so ![3x^{5/7} =\sqrt[7]{3x^{5}}](https://tex.z-dn.net/?f=%203x%5E%7B5%2F7%7D%20%3D%5Csqrt%5B7%5D%7B3x%5E%7B5%7D%7D%20%20%20)
this will be the radical form .
Answer:
x<1
Step-by-step explanation:
You would just subtract 5 from both sides of the equation. The sign does not flip because you are not multiplying or dividing any negative number across the sign. So simply x+5 (-5) < 6 (-5). On the left side the 5 would cancel out. on the other side 6-5 is equal to 1.
Answer: x<1
Answer:
Question 2: 4^12
Question 3: (9/64x)^11
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
secx = 
, cosecx = 
cotx = 
, tanx = 
Consider the left side
secA cosecA - cotA
= 
× 
- 
= 
-
= 
= 
( cancel sinA on numerator/ denominator )
= 
= tanA = right side ⇒ proven
