Answer:
20.6
Step-by-step explanation:
Given data
J(-1, 5)
K(4, 5), and
L(4, -2)
Required
The perimeter of the traingle
Let us find the distance between the vertices
J(-1, 5) amd
K(4, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4+1)²+(5-5)²)
d=√5²
d= √25
d= 5
Let us find the distance between the vertices
K(4, 5), and
L(4, -2)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4-4)²+(-2-5)²)
d=√-7²
d= √49
d= 7
Let us find the distance between the vertices
L(4, -2) and
J(-1, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-1-4)²+(5+2)²)
d=√-5²+7²
d= √25+49
d= √74
d=8.6
Hence the total length of the triangle is
=5+7+8.6
=20.6
Answer:
1/12
Step-by-step explanation:
Given that
30/360 to lowest fraction equivalent
Now, we can write 30 as 3×10
Also, we can write 360 as 36×10
Then, we have
(3×10)/(36×10)
Then, 10 cancel 10, we are left with
3/36
Also we can write 36 as 12×3
Then, we have
3/(12×3)
Also, 3 cancel 3, we are left with
1/12
Then the lowest fraction is 1 / 12
1/12
<h3>
Answer:</h3>
C (see attached)
<h3>
Step-by-step explanation:</h3>
The linear portion of the graph is defined for x ≥ 1, with the point x=1 included. Only selections A and C do that.
The quadratic portion of the graph is defined for x < 1. Only selection C does that. (Selection A is doubly-defined for x > 1, so is not a function. It is undefined for x < 1.)
Answer:
17
Step-by-step explanation:
Work backwards from your instructions
36/9 = 4
4 + 13 = 17
