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3 years ago

How do you solve 2.5x + 10 = 50?

Mathematics

2 answers:

Vsevolod [243]3 years ago

6 0

Answer:

I think the answered is x = 16 hope I right

Veronika [31]3 years ago

4 0

Answer:

X = 16

Step-by-step explanation:

2.5x+10 = 50

distribute the ten to the other side by substracting

2.5x = 50-10

2.5x = 40

Now divide 2.5 on both sides

2.5x/2.5 = 40/2.5

x = 16

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Helpp me please

kiruha [24]

Answer:

d. RP

Step-by-step explanation:

Point p is not on the line.

Therefore RP is not a possible name for the illustrated line

7 0

3 years ago

On a sunny day, a flag pole and its shadow form the sides of a right triangle. if the hypotenuse is 35 meters long and the shado

Triss [41]

We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!

3 0

3 years ago

A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

4 0

4 years ago

Read 2 more answers

I need to know the answer

grandymaker [24]

Answer: $f(x)=-(x-5)^{2}(x+2)$

Step-by-step explanation:

There is a double root at x=5 and a single root at x=-2, so we know f(x) is of the form $f(x)=a(x-5)^{2}(x+2)$ for some constant a.

To find a, we can substitute the coordinates of the y-intercept, (0, -50).

$-50=a(0-5)^{2}(0+2)\\\\-50=50a\\\\a=-1$

So, $f(x)=-(x-5)^{2}(x+2)$

3 0

2 years ago

The diagonals of a rhombus have lengths of 12 centimeters and 16 centimeters. what is the length of one side of the rhombus

Yuki888 [10]

<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>

5 0

3 years ago