B. THE 2 IN THE TENTHS PLACE IS 10 TIMES THE VALUE OF THE 2 IN THE HUNDREDTHS PLACE.
2 2 . 2 2 2
tens ones decimal point tenths hundredths thousandths
2 in the tenths place = 0.20
2 in the hundredths place = 0.02
0.02 x 10 = 0.20
Answer:
1,400,304.726 is the answer
<span>Answer: a) Greater than or equal to 38 feet
b)Since there is no restriction on the perimeter there exists many possible values for the length of the deck.
Explanation: Given that the width of the deck is 29 ft.
and the perimeter of the deck is at least 134 ft.
134 = 2(length + width)
134 = (2 x length) + (2 x 29)
134 = (2 x length) + 58
2 x length = 134 - 58
2 x length = 76
length = 76 / 2
length = 38 ft
Thus, the inequality will be:
a)Length ≥ 38 ft
b)since there is no restriction on the perimeter there exists many possible values for length of deck.</span>
Answer:

Step-by-step explanation:





For the Interval 
Length of the Curve 
Using T1-Calculator
