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Anvisha [2.4K]
2 years ago
12

12. Find the values of x and y in the diagram below.

Mathematics
1 answer:
ehidna [41]2 years ago
8 0

Answer:

x = 15

y = 19

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In a right triangle,the two sides adjacent to the right angle are known as the what? Or and
PIT_PIT [208]

Answer:

Opposite and hypotenuse

Step-by-step explanation:

In a right triangle,the two sides adjacent to the right angle are known as the opposite and the hypotenuse

3 0
3 years ago
3 over 8 multiplied by 10 over 9 multiplied by 16
Gnom [1K]

Answer:

20/3

Step-by-step explanation:

(3/8)*(10/9)*16

This is 30/72 = 5/12

5/12*16=20/3

7 0
1 year ago
Read 2 more answers
Need help now! (probibility)
algol13

Answer:

36%, I'm fairly certian

Step-by-step explanation:

A. 90%

B. 60%

C. 30%

D. 36%

D. makes the most sense to me

6 0
3 years ago
AngleRQT is a straight angle. What are m angleRQS and m angleTQS?<br><br> m angleRQS=
lara31 [8.8K]

\widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 9x + 1 + 7x + 3 = 180 \\ \widehat{RQS}+\widehat{TQS}=\widehat{RQT}\\\Leftrightarrow 16x = 176\Leftrightarrow x = 11 \\ \Rightarrow \widehat{RQS} = 9 \times 11 + 1 = 100° \: \wedge \: \widehat{TQS} = 7 \times 11 + 3 = 80°

4 0
3 years ago
Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b
77julia77 [94]

Answer:

The value is UCL  =  10.8  

Step-by-step explanation:

From the question we are told that

    The sample mean is  \= x  =  9 \  ounce

    The sample size is  n =  25

    The standard deviation is  \sigma =  3 \ ounce

Given that the sample size is not large enough i.e  n<  30  we will make use of the student t distribution table  

From the question we are told the confidence level is  99.7% , hence the level of significance is    

      \alpha = (100 -99.7 ) \%

=>   \alpha = 0.003

Generally the degree of freedom is  df =  n- 1

=>  df =  25 - 1

=>  df =  24  

Generally from the student t distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom of df =  24   is  

   t_{\frac{\alpha }{2} , 24 } = 3.0

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 24} *  \frac{\sigma }{\sqrt{n} }

=>     E = 3.0 *  \frac{3 }{\sqrt{25} }

=>     E =1.8

Gnerally the  upper control chart limit  for 99.7% confidence is mathematically represented as

         UCL  =  \= x  + E

=>      UCL  =  9 + 1.8  

=>      UCL  =  10.8  

     

4 0
2 years ago
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