P(a b)=0.25 and P(b)=0.4, what is P(aub)?
2 answers:
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You can start with the form
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:
7x +2y = 1
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:
7x +2y = 1
9514 1404 393
Answer:
see attachments for a table and graph
Step-by-step explanation:
I find it convenient to use a graphing calculator or spreadsheet to do repetitive computations reliably.
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Your specific question asks for h(0):
h(0) = -|0 +2| +1 = -2 +1
h(0) = -1
You may want to check your other table values.
