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2 years ago

The Pythagorean theorem applies to triangles obtuse right acute

Mathematics

2 answers:

ira [324]2 years ago

4 0

Answer:

Right triangles

Step-by-step explanation:

yawa3891 [41]2 years ago

4 0

Answer:

Right Triangles

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Can someone please help me with this question

blondinia [14]

Answer:

i don't now

Step-by-step explanation:

Sorry I couldn't help you

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2 years ago

Find the 70th term of the following arithmetic sequence.<br><br> 12,17,22,27,...

nikdorinn [45]

Since it starts at 12 and is increasing by 5 each time, the 70th term will be;
12 + 5(70)
12 + 350
362

362 is the 70th term of the sequence.

8 0

3 years ago

Read 2 more answers

Please put a serious answer

aksik [14]

Answer:

x=12

Step-by-step explanation:

9x-14=2(3x+11)

9x-14=6x+22

9x-6x=22+14

3x=36

x=36/3=12

8 0

3 years ago

PLS HELP WITH 4 and 5 ASAPPP FOR BRAINLIEST

topjm [15]

Answer:

4. SAME SLOPE, SAME Y INTERCEPT.

When this happens... The system of Equations has an Infinite Number of solutions.

A IS YOUR ANSWER

A system of Equations has no solution when the graph of the system are PARALLEL LINES.

OPTION D IS YOUR ANSWER.

5 0

2 years ago

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

3 years ago