2 years ago

The Pythagorean theorem applies to triangles obtuse right acute

Mathematics

2 answers:

ira [324]2 years ago

4 0

Answer:

Right triangles

Step-by-step explanation:

yawa3891 [41]2 years ago

4 0

Answer:

Right Triangles

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A and b are positive integers and a–b = 3. Evaluate the following:<br> 27/1/3 b/9/ 1/2 a

DaniilM [7]

Answer:

$\dfrac{1}{27}$

Step-by-step explanation:

Given that,

a-b = 3

We need to find the value of $\dfrac{27^{\dfrac{1}{3}b}}{9^{\dfrac{1}{2}a}}$ .

We know that,

$27=3^3\\\\9=3^2$

So,

$\dfrac{27^{\dfrac{1}{3}b}}{9^{\dfrac{1}{2}a}}=\dfrac{3^3^({\dfrac{1}{3}b})}{3^2^{\dfrac{1}{2}a}}\\\\=\dfrac{3^b}{3^a}$

We know that : $\dfrac{x^p}{x^q}=x^{p-q}$

So,

$\dfrac{3^b}{3^a}=3^{b-a}$

Since, b-a = -3. So,

$3^{b-a}=3^{-3}\\\\=\dfrac{1}{3^3}\\\\=\dfrac{1}{27}$

So, the value of the given expression is equal to $\dfrac{1}{27}$ .

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kogti [31]

Answer:

1. x=8

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Step-by-step explanation:

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