Bob = 12 x T
Sue= 8 (T +2)
12T = 8T + 16
12T-8T=8T-8T +16
4T = 16
4T/4 = 16/4
T= 4 HOURS
PLUG T BACK INTO
12(4) = 8(4) + 16
48=48
DISTANCE = 48 kilometers
Answer:
x=$10
y=$12
Step-by-step explanation:
Step one:
given
let senior tickets be x
and child be y
8x+9y=188----1
also on the second day
x+5y=70-------2
the system of equation is
8x+9y=188-----1
x+5y=70---------2
x=70-5y, put this in 1
8(70-5y)+9y=188
560-40y+9y=188
-31y=-372
divide by -31
y=-372/-31
y=$12
put y= 12 in x+5y=70---------2
x+5(12)=70---------2
x+60=70
x=$10
Answer:
He must score 83 in the last test.
Step-by-step explanation:
To get a mean of 80 Terry must score a total of 4*80 = 320 over the 4 tests.
So his score for the last test must be 320 - (71 + 80 + 86)
= 320 - 237
= 83.
Answer:
940 m
Step-by-step explanation:
Above sea level is measured as positive and below sea level is measured as negative.
In order to find the distance between both we need to find the difference between their elevation and depression.
Distance between Grace and her friend
= 647 - (-293)
= 647 + 293
= 940 m
