15 points!! Look at the picture to see the problem. What do you think?

the relative frequency of a blue on a spinner is 3/5.how many times would you expect a blue in 250 spins

nata0808 [166]

$250\cdot\frac{3}5=\boxed{150\text{ times}}$

8 0

3 years ago

A photo of a beetle in a science book is increased to 735% as large as the actual size. If the beetle is 16 millimeters, what

wariber [46]

Answer: 117.6 millimeters

Step-by-step explanation:

Given , The actual size of beetle = 16 millimeters

Since , the photo of a beetle in a science book is increased to 735% as large as the actual size.

Scale factor to increase the size = 735% = 7.35 [To convert percentage to decimal or fraction we divide it by 100]

Then , the size of the beetle in the photo would be :

(Actual size of the beetle) x (Scale factor)

= (16 millimeters) x (7.35)

= (16 x 7.35) millimeters

= 117.6 millimeters

Hence, the size of the beetle in the photo = 117.6 millimeters

3 0

3 years ago

Choose all of the transformations that would change a triangle into one that is similar, but not congruent. Which transformation

Vsevolod [243]

You didn't supply a list. The so-called rigid transformations of translation, rotation and reflection create congruent triangles.

Generally it's dilation by a factor about a point is preserves similarity but not congruency. Any transformation which includes such scalings but is otherwise rigid also preserves similarity but not congruency.

8 0

3 years ago

Pls help://Evaluate f(1/2), when f(x) = x2

Ulleksa [173]

Answer:

Step-by-step explanation:

f(1/2)=x2

f(1/2)=1/2^2

f(1/2)=1/4

7 0

3 years ago

BRAINLIEST ✨

inna [77]

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.

Step-by-step explanation:

Am I right? just commet if I'm wrong

then TANKYOU>^_^<!

7 0

3 years ago