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joja [24]
3 years ago
13

HELP ITS TIMEDD WILL GIVE BRAINLYIST

Mathematics
1 answer:
serg [7]3 years ago
7 0
I think it’s 110 degrees.
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ABCD is a square What is the length of line segment DC
Softa [21]

Is there a picture to go along with your question, if so post it and i will get back to you.

8 0
3 years ago
Read 2 more answers
Anyone smart at math?
RoseWind [281]

Answer:

The function f(x) = 4.95x represents the cost to purchase x pounds of chocolate from a candy company. The function g(x) = 0.99x + 2.25 models the cost to ship x pounds of chocolate from the company. Write a function, h(x), that models the total cost to purchase and ship x pounds of chocolate from the company.

Step-by-step explanation:

boom it is big now

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3 years ago
When the crispy rice traits have cooled, Mrs. Williams cut them into 30 equal pieces. She gives two -fifths of the treats to her
photoshop1234 [79]

Answer:

She takes 18 to school.

1/5 of 30 is 6 so 2/5 of 30 is 12

30 minus 12 is 18

4 0
3 years ago
A shirt was originally priced at $55. The store is having a 35% off sale. How much will you pay for the shirt after the discount
olga_2 [115]

Answer:

$35,75

Step-by-step explanation:

55 . 35 / 100 = 19,25

55 - 19,25 = 35,75

3 0
3 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
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