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zloy xaker [14]
2 years ago
14

I need a good grade pls help I need help with question 4

Mathematics
1 answer:
Arlecino [84]2 years ago
6 0

Answer:

it b I think tell me if I am wrong

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Round 83.13 to the nearest dollar
kvv77 [185]
It would be $83.00 kid
Have a nice day!!!
5 0
3 years ago
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Which could be used to evaluate the expression Negative 6 (4 and two-thirds)?
Firdavs [7]

Answer:

The answer is (Negative 6) (4) + (negative 6) (two-thirds)

Step-by-step explanation:

So basically, Negative 6x4= negative 24. Then you have to add Negative 6 x two-thirds. So 6 times two-thirds equal 4. So now you just add 24 and 4. And that equals 28. :)

6 0
3 years ago
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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

(\left {{20} \atop {2}} \right. )=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

(\left {{3} \atop {2}} \right. )=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

\frac{3}{190}\\ =0.01579\\=0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

4 0
1 year ago
PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME!!!!!!!! I HAVE 2 QUESTIONS THATS ALL. I WILL GIVE POINTS, FAN, MEDAL. PLEASE I
Soloha48 [4]
F(n)=4n+1 seems to be the basic function for these sets.
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2 years ago
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I need help pleaseeeee
levacccp [35]
The answers is 30 km.....
6 0
3 years ago
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