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zloy xaker [14]
3 years ago
14

I need a good grade pls help I need help with question 4

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

it b I think tell me if I am wrong

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Karen wants to join Buff Gym. There is a $100 initiation fee, and then a $40 monthly fee.
Reptile [31]

Answer:

A) y= 40x+100

B) y=\frac{x-100}{40}

Step-by-step explanation:

To solve this, we can set up an equation using y=mx+b.

'b' is the initial cost, whereas 'm' is the monthly cost. This gives us the equation:

A): y=40x+100.

For part B, we can solve for the inverse by switching the x and y. This gives us:

x= 40y+100

Now, continue simplifying to isolate the 'y' on a side:

x-100=40y

y=\frac{x-100}{40}

6 0
3 years ago
Which expression is equivalent to the following complex fraction?
otez555 [7]

Answer:

Hence, the complex fraction is equal to

[-2y + 5x]/[3x - 2y] that is,

[-2y + 5x] divided by [3x - 2y]

Step-by-step explanation:

Complete Question

Which expression is equal to the complex fraction

[-2/x + 5/y] divided by [3/y - 2/x]

We first take the LCM of each of these

[-2/x + 5/y] = [(-2y + 5x)/xy]

[3/y - 2/x] = [(3x - 2y)/xy]

[-2/x + 5/y] ÷ [3/y - 2/x] becomes

[(-2y + 5x)/xy] ÷ [(3x - 2y)/xy]

= [(-2y + 5x)/xy] × [xy/(3x - 2y)]

= [-2y + 5x]/[3x - 2y]

Hope this Helps!!

5 0
3 years ago
True or False (& Justify): If a ball is thrown horizontally from the top edge of a 150m building at a speed of 25 m/sec, the
kap26 [50]

Answer:

38.6 m/s

Step-by-step explanation:

The motion of the ball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

Therefore we have to analyze the horizontal and vertical motion separately.

Along the horizontal direction, the velocity is constant during the motion, since there are no forces acting in this direction. So the horizontal velocity 3 seconds after the launch will be the same as the velocity at the launch:

v_x = v_0 = 25 m/s

The vertical velocity instead changes according to the suvat equation:

v_y = u_y - gt

where

u_y=0 is the initial vertical velocity

g=9.8 m/s^2 is the acceleration due to gravity

t is the time

Therefore, after t = 3 s,

v_y=0-(9.8)(3)=-29.4 m/s

So the velocity after 3 seconds is < 25, -29.4 > m/s. The magnitude of the velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{25^2+(-29.4)^2}=38.6 m/s

3 0
4 years ago
WILL GIVE BRAINLIEST ASAP
Blababa [14]

Answer:

Step-by-step explanation:

7 0
3 years ago
Factor the trionomial below. X2-2x-48
Murrr4er [49]

Answer:

(x–8)(x+6)

Step-by-step explanation:

= x {}^{2}  - 2x - 48 \\  = (x -8)(x + 6)

3 0
3 years ago
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