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ryzh [129]
3 years ago
7

What is the common difference for the arithmetic sequence?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

The common difference =3

Step-by-step explanation:

The common difference for the arithmetic sequence = 16-13 = 3

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PLEASE HELP!!!<br>what is the length of segment SR? units​
AlekseyPX

Answer:

x=2

Step-by-step explanation:

2x+8=8x-4

2x+12=8x

12=6x

2=x

x=2

4 0
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galina1969 [7]
Both are similar, so Yes.

-All the sides of the squares are equal

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Helppp with 2nd and 4th
DiKsa [7]

Answer:

30

Step-by-step explanation:

so you have multiply 3x7. then you have to add the 9 at the end and there is your answer

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3 years ago
Read 2 more answers
Solve -7u = -21 for u. u =
lesya692 [45]

Answer: u = 3

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Solve for a.
tamaranim1 [39]
The correct answer is:  [C]:  " a =  ± \sqrt{25 - b^2}  " .
<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:  
_________________________________________________________
    </span>→   "  25  =  a²  +  b²  "  ;   Solve for "a" ; 
_________________________________________________________

    →  To solve for "a" ;  we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite:  "  25  =  a²  +  b²  "  ;

as:  " a²  +  b²  = 25 " .

_________________________________________________________
Then, we can subtract " b² "  from each side of the equation; as follows:
_________________________________________________________

   →
 " a²  +  b²  −  b²  =  25 − b²  "  ;

to get:
_________________________________________________________
   →  " a²  =  25 − b²  "  ;
_________________________________________________________
  →  Now,  take the square root of EACH SIDE of the equation ; 
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ; 
_________________________________________________________

  →  √(a²)  = \sqrt{25 - b^2}  ;

to get:
_____________________________________________________
  →    a   =  | \sqrt{25 - b^2} |  ;

  →    a   =  ±  \sqrt{25 - b^2}  ; 
  
  →  which is:  Answer choice:  [C]:  " a =  ±  \sqrt{25 - b^2}  " .
______________________________________________________
8 0
3 years ago
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