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NARA [144]
3 years ago
12

Solve the simulataneous equations. 5x-4y=19 x+2y=8

Mathematics
1 answer:
inysia [295]3 years ago
7 0

Answer:

(5, 1.5 )

Step-by-step explanation:

Given the 2 equations

5x - 4y = 19 → (1)

x + 2y = 8 → (2)

Multiplying (2) by 2 and adding to (1) will eliminate the y- term

2x + 4y = 16 → (3)

Add (1) and (3) term by term to eliminate y

7x + 0 = 35

7x = 35 ( divide both sides by 7 )

x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (2)

5 + 2y = 8 ( subtract 5 from both sides )

2y = 3 ( divide both sides by 2 )

y = 1.5

solution is (5, 1.5 )

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vova2212 [387]
We let y equal to the elevation above sea level so that the elevation of the rock climber after x minutes of climbing would be:

y = 2x + 50

His initial height can be calculated when x is equal to zero it is when the climber is not yet climbing. Therefore, the rock climber'sinitial height above sea level would be 50 meters.
7 0
3 years ago
What is the product of the two matrices? Fill in the missing elements of the resulting matrix.​
olganol [36]

The product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Here we are given the 2 matrices as follows-

\left[\begin{array}{ccc}7&-2\\-6&2\end{array}\right] \left[\begin{array}{ccc}1&1\\3&3.5\end{array}\right]

To find the product of 2 matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

Here since both of the matrices are 2 × 2, their product is possible.

Now, to find the product, we need to multiply each element in the first row by each element of the 1st column of the second matrix and then find their sum. Similarly, we do this for all rows and columns.

Therefore,

\left[\begin{array}{ccc}(7*1)+(-2*3)&(7*1)+(-2*3.5)\\(-6*1)+(2*3)&(-6*1)+(2*3.5)\end{array}\right]

= \left[\begin{array}{ccc}(7)+(-6)&(7)+(-7)\\(-6)+(6)&(-6)+(7)\end{array}\right]

= \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Thus, the product of the given two matrices comes out to be \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Learn more about matrices here-

brainly.com/question/13595915

#SPJ1

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1 year ago
I need help with this asap!
VladimirAG [237]

Answer:1.78

Step-by-step explanation:

4 0
3 years ago
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elena-s [515]

Answer:

The other answer I saw is the same way that I used to explain in my class as well. But, there's an alternative way to reach the answer as well

First thing that we should know is that if there are 'n' units kept in a row, then there are 'n+1' gaps generated by them. So, what we should understand is that when there is no item there is 1 gap, when there is one item there are 2 gaps, and so on.

Let us use that concept here, with a small variation: the 5 shelves are 5 initial gaps. The first book has 5 choices (5 initial gaps) to go to. Once we have placed this book, there are now 6 gaps on which the 2nd book can be placed. After the 2nd book is placed, there are 7 gaps in which 3rd book can be placed, and so on.

So, the total arrangements will be = 5*6*7*...24 [as there are 20 books] = 24P20

8 0
4 years ago
the other three finish painting the kitchen.write an equation to represent a way the four grandchildren.could have shared the pa
olga_2 [115]

Answer:

Step-by-step explanation:

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1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10, 11/11, 12/12, 13/13, 14/14, 15/15 ...

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