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Anastasy [175]
2 years ago
11

Compare the triangles and determine whether they can be proven congruent, if possible, by SSS, SAS, ASA, AAS, or HL. If the tria

ngles cannot be proven congruent choose "cannot be determined."​

Mathematics
1 answer:
Sauron [17]2 years ago
3 0

Answer:

I can't see the picture.

Step-by-step explanation:

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Please help me thank you
Yanka [14]

Answer:

TQ = 83.5

Step-by-step explanation:

11/54 = 17/TQ

11TQ = 918

TQ = 918/11 = 83.45

8 0
3 years ago
Whats is the valume of the created retagular prism
KatRina [158]

Answer:

Formula for the volume of a rectangular prism:

V = length x width x height

To solve, substitute the dimensions given in the problem and multiply.

6 0
3 years ago
2x+3>_7 or 2x+9>11 plzzzz help meee
damaskus [11]

Answer:

b

Step-by-step explanation:

hi I I'm the explanation

4 0
3 years ago
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
A freight train departs from one train station to its destination at a constant speed. Suppose the distance the train is from th
barxatty [35]

Answer:

108 miles

Step-by-step explanation:

Given the points (0.5, 135) and (2,81)

Diatnce between two points :

D = √(x2 - x1)² + (y2 - y1)²

X1 = 0.5 ; y1 = 135 ; x2 = 2 ; y2 = 81

D = √(2^2 - 0.5^2) + (81^2 - 135^2)

D = √(4 - 0.25) + (6561 - 18225)

D = √3.75 −11664

D = 107.98263

D = 108 miles

6 0
3 years ago
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