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pshichka [43]
2 years ago
14

OLEASSEEEE HELPPPPP MEEEE

Mathematics
2 answers:
DaniilM [7]2 years ago
6 0

Answer:

(5x+49)

Step-by-step explanation:

hope that helps

Alexxx [7]2 years ago
5 0

ANSWER

Step-by-step explanation:

UMMMMM IM ACTUALLY IN 6TH GRADE SO YEA IM JUST DOING THIS TO GET MORE POINTS :)

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An example of financial responsibility is
Maurinko [17]

Answer:

keeping financial records organized

4 0
3 years ago
Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

6 0
3 years ago
Can someone help me with this question?<br><br><br> (please explain?
Bogdan [553]
The most accurate way would be the fourth answer, because to estimate 66% of 47 you need to round both as closely as possible. 66% rounds closest to 2/3, and 47 is closest to 48
4 0
3 years ago
Read 2 more answers
Mo puts $1,600.00 into savings bonds that pay a simple interest rate of 3.5%. How much money will the bonds be worth at the end
BabaBlast [244]
18.5 I think so if not then sorry
5 0
3 years ago
PLEASE HELPP!! WILL GIVE BRAINLIEST + 25 POINTS!!
enyata [817]

Answer:

x = -9/4

Step-by-step explanation:

−2(x + 1/4) + 1 = 5 ​

Subtract 2 from both sides.

−2(x + 1/4) = 4 ​

Divide both sides by -2.

x + 1/4 = -2

Subtract 1/4 from both sides.

x = -2 1/4

x = -9/4

4 0
3 years ago
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