All categories

3 years ago

The first step in the process for factoring the trinomal x^2-3x-40 is to ?

Mathematics

1 answer:

bogdanovich [222]3 years ago

8 0

Answer:

X^2-3x-40=0

(x-8)(x+5)

X=8,x=-5

You might be interested in

HAVE TO TURN IN TODAY PLZ HELP

erma4kov [3.2K]

The area equation is $A = \pi (4)^{2}$ , which when solved equals 50.24. That's the third answer on your list.

5 0

3 years ago

The ratio of boys to girls at a movie is 7:10. If there are 49 boys at the movie, then how many girls are at the movie?

jeka57 [31]

Answer:

¯\_(ツ)_/¯

Step-by-step explanation:

3 0

3 years ago

This question has two parts. First answer Part A Then, answer Part 8

8_murik_8 [283]

Answer:

In part A first do addition of all 3 then add the no 6,2,3 then minus both the ans then you will find the final ans

6 0

2 years ago

Solve for each system of equations by substitution or elimination.

Tems11 [23]

QUESTION 1

The given system of equations are:

$y=x^2+5x+1$

$y=x^2+2x+1$

We equate the two equations to get:

$x^2+5x+1 =x^2+2x+1$

$x^2 - {x}^{2} + 5x - 2x = 1 - 1$

$3x = 0$

$x = 0$

When x=0,

$y=0^2+2(0)+1 = 1$

The solution is (0,1)

QUESTION 2

The given equations are:

$y=x^2-2x - 1$

and

$y= -x^2-2x-1$

We equate both equations to get:

$x^2-2x - 1 = -x^2-2x-1$

Group similar terms,

$x^2 + {x}^{2} -2x + 2x= -1 + 1$

$2 {x}^{2} = 0$

$x = 0$

We put x=0 into any of the equations to find y.

$y= -0^2-2(0)-1 = - 1$

The solution is (0,-1).

QUESTION 3

The given equations are:

$y=x^2+2x+1$

and

$y=x^2+2x-1$

We equate both equations:

$x^2+2x+1 = x^2+2x-1$

Group similar terms:

$x^2 -x^2+2x = -1 - 1$

$0 = -2$

This is not true.

Hence the system has no solution.

6 0

3 years ago

+ (−) = <br><br> n = <br> HELP MEEEEEE PLSSS

Korolek [52]

Answer:

Step-by-step explanation:

a positive multiplied by a negative will always give you an answer of a negative number. thats the only logical answer i can think of

4 0

2 years ago