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tamaranim1 [39]
3 years ago
14

Help please rn help

Mathematics
1 answer:
aksik [14]3 years ago
8 0

Area of the large semicircle

= \pi{r}^{2}  \div 2

=  \frac{22}{7}  \times 12 {}^{2}  \times  \frac{1}{2}

=  \frac{11}{7}  \times12 \times 12

=  \frac{11}{7}  \times 144

= 226.28

Area of the small semicircle

= \pi  {r}^{2}  \div 2

=  \frac{22}{7}  \times 6 {}^{2}  \times  \frac{1}{2}

=  \frac{11}{7}  \times 6 \times 6

=  \frac{11}{7}  \times 36

= 56.57

Area of the figure

= 226.28 - 56.57

= 169.71 {cm}^{2}

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The solution on the graph is (x,y)=(7,25), so x=7.

a. \\
3x+4=5x-10 \\
3x-5x=-10-4 \\
-2x=-14 \\
x=\frac{-14}{-2} \\
x=7 \\ \\
b. \\
3x-4=5x-10 \\
3x-5x=-10+4 \\
-2x=-6 \\
x=\frac{-6}{-2} \\
x=3 \\ \\ c. \\
3x+4=5x+10 \\
3x-5x=10-4 \\
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x=\frac{6}{-2} \\
x=-3 \\ \\
d. \\ 
3x-4=5x+10 \\
3x-5x=10+4 \\
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x=\frac{14}{-2} \\
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x=7 in the equation a, so the answer is A.
6 0
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