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3 years ago

Tell whether the lines for each pair of equations are parallel, perpendicular, or neither.

Mathematics

2 answers:

Olin [163]3 years ago

6 0

I hope this helps you

Luba_88 [7]3 years ago

4 0

The first equation is already solved, the slope is -1/4

The second equation you need to rearranged the numbers..

-2x+8y=4
8y=2x+4 now divide by 8
Y=4x+2

Which makes the answer perpendicular because they are both different signs and are swapped.

Hope this helps :)

You might be interested in

Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6.

lubasha [3.4K]

Y = mx + b
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
-3 = 12 + b
-3-12 = b
-15 = b

so ur equation is : y = -6x - 15

7 0

3 years ago

Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰

Valentin [98]

$-17^0=(-17)^0=1$ $\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}$

Thus, the final answers are 1 and -1/8.

4 0

10 months ago

Allison is rolling her hula hoop on the playground. The radius of her hula hoop is 35 cm. What is the distance the hula hoop rol

lidiya [134]

Answer:

Distance covered by hula hoop rolls in 4 full rotations is 880 cm .

Step-by-step explanation:

Formula

$Perimeter\ of\ a\ circle = 2\pi r$

Where r is the radius of the circle.

As given

Allison is rolling her hula hoop on the playground.

The radius of her hula hoop is 35 cm.

r = 35 cm

$\pi = \frac{22}{7}$

Putting the value in the formula

$Perimeter\ of\ a\ hula hoop = 2\times \frac{22}{7} \times 35$

= 220 cm

As given

The hula hoop rolls in 4 full rotations.

Distance covered by hula hoop rolls in 4 full rotations = 220 × 4

= 880 cm

Therefore the Distance covered by hula hoop rolls in 4 full rotations is 880 cm .

6 0

3 years ago

What's the answer to this? and please explain.

vichka [17]

<h3>Answer: No, there isn't enough ribbon</h3>

===========================================================

Use this formula

a & b/c = (a*c+b)/c

to convert from a mixed number to an improper fraction

So,

a & b/c = (a*c+b)/c

3 & 3/4 = (3*4+3)/4

3 & 3/4 = 15/4

---------------------------------------------------

Next, we add the fractions 15/4 and 5/6. The denominators aren't the same, so we can't add right away. We need to get the denominators to the LCD.

In this case, the LCD is 4*6 = 24

The fraction 15/4 becomes 90/24 after multiplying top and bottom by 6.
The fraction 5/6 becomes 20/24 after multiplying top and bottom by 4

Now we can add the fractions:

90/24+20/24 = (90+20)/24 = 110/24

---------------------------------------------------

So far, we've added the 3&3/4 portion to the 5/6 portion to get the result 110/24

The last thing to do is to add on the two 1/3 ft pieces, which means we're adding on 2/3 of a foot

2/3 = 16/24 after multiplying top and bottom by 8

Add this to the result of the last section

110/24+16/24 = (110+16)/24 = 126/24

---------------------------------------------------

From here, we convert the improper fraction 126/24 to decimal form

Using a calculator, you should find that 126/24 = 5.25

The result is larger than 5, which means she used too much ribbon. There won't be enough ribbon to do everything she wants to do.

---------------------------------------------------

The shortcut we can take is to type the following into the calculator

3+3/4+5/6+2/3

doing so should lead to 5.25

5 0

3 years ago

Read 2 more answers

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

3 0

3 years ago