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dybincka [34]
3 years ago
11

Find the Area of the figure below, composed of a rectangle with two semicircles

Mathematics
1 answer:
Julli [10]3 years ago
5 0

Answer:

61.7

Step-by-step explanation:

i had this question on the exact delta math thing and its 61.7,i dont know how to do it its complicated.

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Apply the zero product property to solve the equation below:<br> x (x + 2) = 0
True [87]

Answer:

0(-2+2)=0

Step-by-step explanation:

x=0

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0(-2+2)=0

3 0
2 years ago
What do I have?<br> what do I need ?<br>what should I use?
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For a:
you have your opposite side
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What is 4x -1/2<br> =x+ 7
gogolik [260]

Answer:

Step-by-step explanation:

Bringing like terms on one side

4x - x = 7 + 1/2

3x = 7.5

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Write 48 ten thousands, 21 hundreds, and 7 tens in word form and expanded form.
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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Factor 7(x − 3)2 − 4(x − 3) − 3 completely.
Nezavi [6.7K]
7(x-3)^2-4(x-3)-3\\\\substitute\ t=x-3,\ then\ we\ have\\\\7t^2-4t-3\\\\a=7;\ b=-4;\ c=-3\\\\\Delta=b^2-4ac\\\\\Delta=(-4)^2-4\cdot7\cdot(-3)=16+84=100\\\\t_1=\dfrac{-b-\sqrt\Delta}{2a};\ t_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\t_1=\dfrac{-(-4)-10}{2\cdot7}=\dfrac{4-10}{14}=\dfrac{-6}{14}=-\dfrac{3}{7}\\\\t_2=\dfrac{-(-4)+10}{2\cdot7}=\dfrac{4+10}{14}=\dfrac{14}{14}=1\\\\7t^2-4t-3=7\left(t+\dfrac{3}{7}\right)(t-1)=(7t+3)(t-1)\\\\=(7(x-3)+3)(x-3-1)=(7x-21+3)(x-4)\\\\=\boxed{(7x-18)(x-4)}
7 0
4 years ago
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